Sorry, but you are getting science
What are the dimensions of this island?
You gods are human body shaped, floating in the ocean. An adult has a body surface area of 1.5 to 2 m$^2$. Lets say roughly 1/3 of that facing 'up' as the body is floating; that means the surface area facing up is about 0.6 m$^2$. Average human height is around 1.6 m, width is 0.4 m and depth is 0.2 m.
Your god-island-person is 304 mi$^2$, or $7.9\times10^8$ m$^2$. At this ratio, your island is about 58 $\times$ 14 kilometers.
Also important is a mass estimate. Using the same ratio, and an average human mass of 70 kg, I get $3.3\times10^{15}$ kg. Since you want the island to float, it can't weight much more than this, since the human body's density is just below that of water.
How will waves affect an island this big?
The important concepts are wavelength and wave height. For wind waves, even the strongest storms with sustained winds above 100 km/h won't produce wavelengths much longer than 200m.
The wavelength is important because of what is happening under the god-island. If the waves are striking along the shortest axis, the 14 km across the waist, then there are about 70 wavelengths passing underneath the island. That means that there are 70 'peaks' of water that are holding up the body of the island. The island will not be caused to rock back and forth, because even when one wavelength passes out from under the end of the island, there are still 69 points of contact holding the island steady.
What about big waves?
Tsunamis, on the other hand, will have an effect. A tsunami can have a wavelength up to 200 km, due to the speed at which the wave propagates. Therefore, it can have the power to lift the entire island up. The tsunami that hit Japan causing the Fukushima meltdown was about 10m high; parts of it were up to 40m high. Lets see what the effect of a 10m and 40m tsunami wave with wavelength longer than the island would have.
There would be two effects imparting energy to the system. Once the island was lifted up on one end by the tsunami wave, and after the wave passed and normal sea level was returned, there would be an end in the air, pulled down by gravity, and an end in the water, pushed up by buoyancy. Modeling the body as a rod, we can divide it into two systems, each with their own energy contribution.
The end lifted out of the water will fall back down by gravity. Assuming it has half the total mass, and is lifted to an average height of 1/2 the wave height, we can calculate its potential energy of $$mgh = 1.6\times10^14 \text{ kg}\cdot9.8\text{ m/s}^2\cdot5m = 7.8\times10^{15} \text{J}.$$
The force exerted by buoyancy is $(\rho_f-\rho_o)V$ where $\rho_f$ is the density of seawater, $\rho_f$ is the density of the seawater; $\rho_o$ is the density of the object (god-island); and $V$ is the submerged volume. Assuming roughly half of your god-island-bar is submerged, the total volume is about $5.7\times10^{12}$ m$^3$. Seawater is about 1020 kg/m$^3$, whereas a god-island-body is 985 kg/m$^3$.
Muliplying this force by the same vertical displacement, we get $$Fh = (1020-985\text{ kg/m}^3)\cdot5.7\times10^{12}\text{ m}^3\cdot9.8\text{ m/s}^2\cdot5\text{ m} = 9.8\times10^{15} \txt{ J}.$$
Add these together, we see that the tsunami has imparted about $18\times10^{15}\text{ J}$ to the island, equivalent to a magnitude 8 earthquake.
Conclusion
The normal wind and waves will not even faze your island. Even the most powerful typhoon can't whip up waves strong enough to make the residents of your god-island notice.
However, a magnitude 9 earthquake in the nearby ocean could. The resultatnt effects to the island are equivalent to a magnitude 8 earthquake. This sounds bad, but massive tsunami's are relatively rare, and it is not as if the ancient Chinese whose technology level you are copying never got hit by such an earthquake.
All in all, no change is necessary. Buildings can be made as if they were on Earth, just expect them to be damaged by infrequent earthquakes, just as they are on Earth.