How much we need?
Rounding down Moon to a roughly flat ball with the average distance to the planetoid center and then making a hollow sphere to the highest elevation via math gives us the estimated volume of liquid we need to fill. So:
$V=\frac{4 \pi}{3}(R_{peak}^3-R_{sea}^3)$
Taking 1737.4 km for moon sea level, the highest point goes 10.786 km above that. This gives a volume of:
$V=411722695.8934 \text{ km³}$
That only fills to just about the top of the highest mountain, demanding 5 km coverage, brings it to a generous $V=604296935.9922 \text{ km³}$, so your preferred solution is somewhere between those two extremes.
In other words: it's a huge lot of liquid. If that would be water with a density of $\rho=1 \frac{\text t}{\text m^3}$, it would weigh ${4.1 \choose 6.0} \times 10^{16}\text t$. That is still much less than the weight of the moon (which ranges in the $10^{19}\text t$ area), but it is a considerable fraction: you would add about $\frac {1 \to 2} {1000}$ of the mass of the moon itself if you take water.
Adding that much weight would have a substantial effect on the Moon-Earth system though, resulting in a decaying orbit and crash on a long term timescale, but that would be a better question for Randall Munroe, who might dedicate that question of world destruction a blog entry. So I skip on that and go to what our ocean has to endure.
Environmental Problems...
Obviously, water will freeze due to being exposed to an environment of at coldest $26 \text K$ on the surface of the moon and $3 \text K$ at the surface to outer space. To complicate things, fluids start to evaporate much earlier (as much as close to $0 \text K$ for Hydrogen) due to reduced pressure. And above that, the Moon's surface gets very very close to $400 \text K$ in the sun, because rock is a very very bad thermal conductor.
In the end, pouring all the water onto moon will just help in creating a jagged ice crust that more resembles an uneroded Europa than a liquid. Why uneroded? Europa encounters daily tidal forces, just like Tethys, which keep the inner water layers of the planetoid in a liquid state due to the extreme magnetic fields of the gas giants they rotate around. Earth can't grant that field - and both these snowballs have an outer crust of ice, not a fully liquid ocean, so the water solution is kind of out.
What to take?
So we got to take something that doesn't boil away, gets blown off the moon by the solar wind and doesn't freeze to solid by exposure to the temperatures. But here is the problem: there are not too many substances that are in liquid state in an environment facing to the $3 \text K$ and near vacuum environment of outer space... actually I could come up only one single material that actually is a liquid in an environment close to that: Helium boils at $4.22 \text K$ and remains liquid till very very close to absolute 0. it would weigh 0.125 tons per m³... but that is at 1 Atmosphere pressure, while we got a 0 atmosphere out at the upper edge of our ocean, which again... makes our precious ocean boil away due to reduced boiling point.
Hydrogen (which boils at $20 \text K$) is not an option, as it freezes at $14 \text K$.
End of the line
No, you can't create a fluid ocean on moon, as it has neither a protective magnetic field (which would keep the sun wind away to allow the creation of an atmosphere and thus any pressure at all), nor is there a liquid that would be fluid in the whole $3 \to 24 \text K$ temperature range that we can expect on coldest point, and especially there is no substance that is liquid for the whole $3 \to 400 \text K$ range that we have to deal with on the day side. This does ignore the temperature averaging effect of the fluid though, but still:
No Atmosphere = No oceans in fully fluid state.