I'm making this up as I go along, so bear with me.
The light received by a planet when one star eclipses another depends on how much of the background star is blocked by the foreground star, which depends on the relative sizes of each and the line-of-sight angle from the planet, and on the brightness of each star, of course, and on the distance from the planet at each point.
This is rather complicated as it is, so let's assume the planet's orbital inclination is zero with respect to the star pair, i. e. the planet orbits on the same plane as the two stars so there will be an eclipse every time and it will be seen "head on". If the (apparent) larger star eclipses the (apparent) smaller one, of course, the solution is trivial.
In any case we need to know how large each star looks from the planet at the time of each eclipse. From a large distance $r$, the angular diameter of a body with actual diameter $d$ is $\delta = {r / d}$ (in radians).
Suppose stars have absolute brightness values $b_1$ and $b_2$. Units don't matter; we can express them relative to our Sun's brightness. Since the actual energy received will vary with the reciprocal of the square of the distance, you will have to calculate that. Again, we can choose relative units and measure distance in terms of the Earth-Sun system, e.g. treat distance as measured in AU.
For brightness $b$ and distance $r$, the planet will receive an effective amount of energy of $b / r^2$ (relative to Earth) from each star.
When there's an eclipse, the planet receives the full amount of energy from the foreground star ($b_1$) at its minimum distance ($r_1$), plus the energy corresponding to the part of the background star that is not eclipsed, if any. So this would be the answer to your question, expressed in terms of the relative brightness of both stars with respect to the Sun:
$$ b_{total} = {b_1 \over r_1^2} + \Delta\delta {b_2 \over r_2^2} $$
where $\Delta\delta$ is the relative difference between the angular diameter of the background star and the foreground star:
$$ \Delta\delta = {{r_2 d_1} \over {r_1 d_2}} - 1 $$
(as I said in the beginning, this is assuming the smaller star is passing in front of the larger one; if the reverse is true, $\Delta\delta = 0$). I'm using this because the difference between the angular diameters of each star determines how much of the background star is visible from the planet, and thus roughly how much of the star is sending photons towards it. I'm aware this might be a terribly crude of approaching it, but I don't think it wouldn't work as a nice first approximation.