TLDR: Radioisotope thermoelectric generator (RTG) with polonium($\ce{^{210}Po}$) instead of plutonium($\ce{^{238}Pu}$) cooled by liquid lithium is a superior power source for any power armour. More detailed conclusion is at end.
Setting
Humanity has conquered the Solar system but has a long way to go before becoming an interstellar species. The Jovian moons, Mars, annd the asteroid belt are colonised, but Titan is not.
Technology levels are similar to Expanse, but without the protomolecule and with a bit more constrained interplanetary transportation.
Gravitational wells of the planets are still serious obstacles. I tried to design the warfare so that it favours small-scale operations that are best done with dedicated military units to exploit speed and mobility.
Naturally, such a state of affairs nudges technological development into focusing as much military might into a single person as possible, thus the power armour.
EDIT: As this tech is quite expensive, power armour is not used by standard infantry, but rather by shock troops to reach dedicated objectives. These include, but not limited to: initial assault from orbit, breach crews for spaceship and station boarding, sabotage. One might say, that toxic nature of the fuel and coolant forbids massive adaptation of this technology even if somebody is rich enough to afford it.
Power armour
The picture above by ukitakumuki is the best depiction of what I understand as a power armour that I could find on the internet.
However, there is a well-known problem that is faced by any power armour design. The source of power. This tiny backpack in the image above can't hope to supply enough energy without some sort of Clarke magic $^1$ that derails the whole setting.
Power source
TLDR: Accumulators, fuel cells and modern RTGs are unsuitable.
I invite you to ignore the backpack design above and imagine how this thing can actually be powered.
Let's get some rough numbers for a baseline. There is no power armour in real life, but there are exoskeletons and accumulators.
From this article it is possible to infer that the energy consumption of an exoskeleton is in kilowatts.
Power armour is, conceptually, an exoskeleton that carries defense plates, power supply, computers, and weapons. Computers are not particularly power hungry, defense plats and weapons could also eat no energy. So, in a basic setup, one needs to power nothing, but an exoskeleton.
$$ W_{exo} \approx 5 kW $$
Li-ion accumulators
TLDR: Power armour needs half a ton of accumulators for a 24-hour mission. Too much.
From another article it is possible to extract some accumulator data for electric cars. Namely specific energy($W_{se}$) and specific power ($W_{sp}$) and volume-specific power($W_{vsp}$.
$$ W_{se} = 155 \frac{Wh}{kg} $$ $$ W_{sp} = 0.71 \frac{kW}{kg} $$ $$ W_{vsp} = 2.52 \frac{kW}{L} $$
With today's technologies, the power supply should be at least $m = \frac{W_{exo}}{W_{sp}} = \frac{5}{0.71} = 7 kg$, not so bad. But this is just to ensure a continuous function. For the deployment time of $t_h = 24$ hours the mass of accumulators should be about $m = \frac{W_{exo} \cdot t_h}{W_{se}} = 774 kg$.
Ouch, this is definitely too much.
Hydrogen fuel cells
TLDR: Power armour needs over 500L of modern hydrogen fuel for a 24-hour hour mission. Moreover, compressed hydrogen itself is a bad idea for a combat situation.
Following a very informative report it is possible to infer stats for a modern system of hydrogen fuel cells.
$$ m_{cell} = 43 kg $$
$$ W_{sp} = 2.9 \frac{kW}{kg} $$ $$ W_{svp} = 3.37 \frac{kW}{L} $$
The fuel cell could be fuelled. The tricky part is to choose how much hydrogen is compressed and how much to store. Because the more it is compressed, the more energy-dense the fuel is. However, if compressed, it explodes upon mechanical impact. Not a good quality for a part of power armour.
Modern energy density of $\ce{H_2}$ fuel is around $4.5 \frac{kWh}{kg}$, and $225 \frac{Wh}{L}$, which is similar to $205 \frac{Wh}{L}$ of electric car accumulators. At this pressure the hydrogen mass-to-volume ratio is $0.05 \frac{kg_{H_2}}{L}$.
So, let's see how much mass and volume one should take for a $t_h = 24$-hour mission.
$$ m = 43 + \frac{5 kW \cdot 24 t_h}{4.5 kW} = 43_{cell\ mass} + 26.6_{fuel\ mass} = 69.6 kg $$
Now, the fuel volume:
$$ V = \frac{26.6}{0.05} = 533 L $$
Here is a 500-litre tank for reference.
One can compress hydrogen further and even liquify it. But then, cooling and/or safe storage are of critical importance. One well-aimed projectile and the whole thing explodes and then sets ablaze if oxygen is present. Furthermore, this is unlikely to significantly change with improved technologies as hydrogen is fundamentally hard to handle and the fuel efficiency is already relatively high(about 40%-60%).
Thus, I say the fuel cell is out.
RTGs, my beloved
TLDR: Too little power
Today radioisotope thermoelectric generators are used in space, there are many variants, but I will use MMRTG as a reference point.
Almost all of them use plutonium as it has several very important features that are very handy in space missions.
- Has long half-life: 87.7 years
- Undergoes almost exclusively $\alpha$-decay
The stats for MMRTG with $^{238}Pu$ are as follows:
$$ m = 45kg $$
$$ W = 0.125 kW $$
$$ W_{sp} = 0.0028 \frac{kW}{kg} $$
$$ W_{vsp} = 0.022 \frac{kW}{L} $$
This is quite low and can't power any kind of power armour.
Speculation about RTGs
TLDR: Polonium provides plenty of energy for a considerable amount of time and can be manufactured from stable components on site. However, it needs to be cooled to ensure RTG does not melt. Water is not sufficient, lithium is a better alternative. Lastly, its radiotoxic qualities are manageable as alpha radiation is detectable and extraterrestrial environments are naturally resilient to contamination.
First, let's examine another good, modulo extreme toxicity, candidate material for RTG fuel: polonium, more precisely $^{210}Po$. It also undergoes almost exclusively $\alpha$-decay, but unlike plutonium, its half-life is only 138 days$^2$. All polonium below is assumed to be of this isotope unless specified otherwise.
The short half-life is quite good actually, the power output from it is much higher than from plutonium. The downside is that one can't store it and needs to produce it on-site from stable bismuth via neutron bombardment. For a reasonably timed mission, it is more than enough. However, if the mission is expected to be longer than a month and supplies are scarce, then no luck.
The MMRTG itself has quite moderate weight and size as one can see in the picture above. The tricky part with polonium is to cool it down as it obviously emits much more thermal power compared to plutonium.
There are existing designs for polonium RTG, but they are old and for space. It seems like they do not reflect the extent of power harvesting that is possible with polonium fuel as they are limited by their field of application.
Energy output
TLDR: Polonium energy output is not only enough for exoskeleton baseline, but permits wet mass over 2 tons while preserving ability to run.
Thus, for speculation, let's just scale existing MMRTG to polonium based on the power-to-volume ratio.
The thermal power density of polonium is $140 \frac{kW}{kg}$ instead of $0.54 \frac{kW}{kg}$ for plutonium. Accounting for density, the scale factor for specific energy outputs is as follows: $$ scale = \frac{W_{Po\ thermal} \cdot \rho_{Po}}{W_{Pu\ thermal} \cdot \rho_{Pu}} = 120 $$
And the stats themselves:
$$ W_{sp} = 0.33 \frac{kW}{kg} $$
$$ W_{vsp} = 2.64 \frac{kW}{L} $$
These numbers approach those of accumulator but with no drawback of limited capacity. The decay continues without stopping and the degradation of the power supply won't bother the wearer for weeks.
And for the whole thing $W_{Po} = 125 W * 120_{scale} = 15 kW$. Seems perfect for $W_{exo}$.
To put these numbers into perspective let's see what are mass limitations for this thing to run. The power output of running humans is provided by table here, as one can see it is a good estimate to have $W_{running} = 5 \frac{W}{kg}$. Assuming modern electrical motor efficiency of $\alpha = 0.75$ the wet mass of the soldier is as follows.
$$ m_{wet} = \alpha \frac{W_{Po}}{W_{running}} = 2.25 \text{ tons} $$
This is a lot of room for equipment.
Production
TLDR: Polonium production could be done in the field from stable materials on demand.
An interesting paper explores a very efficient way to produce polonium, as found by @Vesper. It suggests a self-sustaining reaction in bismuth beryllium acetate. There are few details in the paper regarding this substance, so I assume it is a mixture of bismuth acetate $\ce{C6H9BiO6}$ with beryllium acetate $\ce{C4H6BeO4}$ in some undisclosed proportion. These are stable compounds that are very transportable.
Magic happens when polonium is added to the mixture. The process goes as follows.
- Polonium decays and emits high energy(5.4 MeV) $\alpha$-particle. This turns polonium into lead.
- High energy $\alpha$-particle interacts with $\ce{Be}$ and get turned into neutron, producing stable $^{12}_6\ce{C}$ carbon. $\alpha$ -particles and resulting neutrons also interact with light elements(thus acetate) to create even more neutrons and fine-tune existing ones to suitable energies(read the paper for details).
- Resulting neutrons interact with $\ce{Bi}$ creating its unstable isotope that shortly decays into precious $\ce{Po}$
The paper claims that not only it is possible to effectively produce polonium in this way, but also quite easy to extract. Far easier than from a molten metal mixture of reactor coolant.
The paper lacks details on the values for their theoretical model that were determined by the experiment. Still, judging by their graphs, it is safe to assume that a considerable portion of bismuth was turned into polonium after 50 hours of reaction time.
Let's approximate some yields. Molar masses are $\mu_{Bi\ acetate} = 386.11 \frac{g}{mol}$, $\mu_{Be\ acetate} = 127.1 \frac{g}{mol}$ . Densities are unavailable, so I will assume something like $\rho = 1.75 \frac{kg}{L}$ following calcium acetate and other similar metal compounds.
So, assuming $V = 100 L$ container of the 50/50 mixture w.r.t molar masses is a standard supply pack, the following mass of bismuth acetate is present.
$$ m_{BiA_3} = \frac{V \cdot \rho}{1 + \frac{\mu_{BiA_3}}{\mu_{BeA_2}}} = 43 kg $$
Then bismuth acetate substance amount is $\frac{43 \cdot 10^3}{389.11} = 112 \text{ mol}$, with single bismuth per molecule the with molar mass of bismuth being $\mu_{Bi} = 209 \frac{g}{mol}$ overall bismuth mass is as follows.
$$ m_{Bi} = 112 \text{mol} \cdot \mu_{Bi} = 23.5 \text{ kg} $$
As polonium is produced the mass slightly changes, but it should be less than a percent due to the single nucleon difference.
If plutonium is replaced by polonium in MMRTG with volume preservation, its mass would be 2.4 kg per RTG. Overall, this means that from a single 100L container, after a little more than two days of waiting, one can produce polonium to fuel $\frac{23.5}{2.4} = 9.8$ fresh RTGs.
This is, of course, assuming all bismuth is turned into polonium, and it is quite reasonable to assume high efficiency, but even if this container turns only half bismuth into polonium it is enough to refill a full squad of five power armour wearers. Moreover, they themselves can trigger the production by just unloading their depleted RTGs into the supplied container.
No need to transport hot pieces of equipment fuming with lithium as the fuel can be made right before deployment. One can't stop existing ones, but these can be recycled or safely stored.
Thus, I call success on production possibilities.
Cooling
Disclamer: The cooling is actually the most problematic part. There are few mistakes in the section below, but the results are mostly correct. I hit character limit, so for corrections, more armour depictions, $\ce{LiH}$ coolant, and more nuanced calculations, please, go here.
TLDR: Water is not efficient enough as a coolant, lithium is almost ten times more effective.
It is easy to have radiation shielding for alpha decay, but it is much harder to deal with heat.
The thermal power of polonium is two orders of magnitude stronger than that of plutonium. With a 6.25% efficiency of MMRTG, if one would use water to remove heat by evaporation, the water would need to dissipate about $120_{scale} * 2\ kW_{Pu\ thermal} = 240kW$ of continuous heat.
Good thermoelectric elements are themselves thermal insulators. With advanced material science, it is not a long stretch to assume that it is possible to thermally isolate a human wearer from the power source. This does not solve the task of preventing an RTG from melting but allows the use of more exotic coolants that can operate at higher temperatures.
Suggestions for cooling materials are welcome by the way.
Water
Accounting for evaporation energy of the water $E_{\ce{H2O}} = 40 \frac{kJ}{mol}$ and its molar mass $18 \frac{g}{mol}$. It turns out that the water loss would be about $\frac{240 \cdot 18}{40} = 108 \frac{g}{s}$ means that for a 24-hour mission, one would need to take 400 kg of water. Too much.
Lithium
Turns out lithium is almost ten times more effective per kilogram. Evaporation energy $E_{\ce{Li}} = 136 \frac{kJ}{mol}$ with a molar mass of $6.9 \frac{g}{mol}$ its loss is going to be only $\frac{240 \cdot 6.9}{136} = 12 \frac{g}{s}$ with demand for a 24-hour mission being "only" 43 kg with a volume of 81 liters.
The boiling point of lithium is 1330 °C. There is a handy paper about lithium evaporation which allows inferring that, near the boiling point, lithium evaporates with speed in grams per second from each square centimeter. Precise value is hard to recover and, honestly, is excessive. The result is that for successful cooling lithium evaporation could be sufficient.
Polonium salting
Unfortunately, the boiling point of polonium is only 962 °C. Nobody wants to handle boiling polonium, this is ridiculous. Polonium fissions into lead and this process naturally increases boiling point, but the process is slow. I found very little information about polonium compounds, for example, density values are nowhere to be found.
There is one polonium compound with thulium $TmPo$. It is reported to have a melting point of 2200 °C. My speculation is that it is possible to "salt" polonium with it to increase boiling point in a similar manner we salt water. This is purely my speculation and I have nothing to support it in terms of papers or articles.
Compensating burst movements
One way to reduce coolant needs is to reduce heat emission, but it reduces the electric power. However, for any device, including power armour, peak and average loads exist. This means that it is impossible to effectively use all available $W_0=15$ kW without storing some of it. For calculations below the fully loaded configuration, which uses all $W_0$ while running, is assumed.
Walking and running, naturally, use different amounts of power. As specified above, running is about $W_{running} = 5 \frac{W}{kg}$, while here it is reported that $W_{walking} \approx 2.5 \frac{W}{kg}$ for $2 \frac{m}{s}$. It could be immediately inferred that walking uses half of $W_0$ in a fully loaded configuration.
We cut the polonium RTG by $0 \lt a \lt 1$ in size and energy output. This reduces power output and coolant consumption.
It is reasonable to assume that power armour with depleted accumulators should permit walking. Thus, $a \gt \frac{W_{walking}}{W_{running}} = 0.5$.
To ensure that the burst power is still $15$ kW the following equation must hold.
$$ W_{sp}^{acc} = 0.71 \frac{kW}{kg} $$
$$ W_0 = a \cdot W_0 + m_{acc}\cdot W_{sp}^{acc} \iff m_{acc} = 21.2 \cdot (1 - a) \text{ kg} \implies m_{acc} < 10.6 \text{ kg} $$
The maximum burst time in seconds is $t_b = \frac{m_{acc} \cdot W_{se}^{acc}}{(1 - a) \cdot W_0} = \frac{2 \cdot 10.6 \cdot 55.8 \frac{kJ}{kg}}{15 kW } = 78.9 \text{ s}\approx 1.3 \text{ min}$, with the same recharge time, while idle.
So, It seems like accumulators are just not worth it to compensate for burst movements. Some power can be stored for an occasional consumption spike by equipment, but running is just too power-hungry.
The above assumed that accumulators are occupying extra space that is produced by downsizing an RTG. Potentially, nothing forbids to just take more to reduce lithium consumption. This is not effective volume-wise though.
Radiotoxicity of polonium
Disclaimer: I must confess that I do not have much expertise in biology or medicine, thus I welcome any suggestions on how to improve the analysis below.
TLDR: Decontamination by itself happens after less than six year. There are way to effectively detect and combat polonium spread even today. Extraterrestrial habitats are naturally tolerant to radioactivity.
First, let's investigate how deadly polonium is.
The first thing to mention is that polonium is almost exclusively an alpha emitter and does not pose a danger outside of living tissues. Exceptions for humans are eyes and, I assume, mucous membranes.
Practically this means that it is enough to have breathing gear and some skin protection to avoid exposure. Power armour application domain lies well beyond Earth, so it is natural to assume that space suit is a norm.
Extreme radiotoxicity establishes itself when polonium is ingested, inhaled, or absorbed otherwise. There is a promising antidote, but it is best to avoid situations where one needs it.
Lethal doses are small, but upper limit for safe dose is more interesting and it is as small as 6.8 pico grams.
The immediate conclusion here is that it is impossible to have a polonium-based power source that surely contaminates the area in case of a leak. After the battle took place it is safe to assume that some of the fallen wore power armour and their RTGs are surely raptured.
Below I am going to explore why I think that this conclusion is premature.
Natural decontamination due to decay
Polonium decays into lead, so let's see after what time lead poisoning would be more probable than polonium poisoning.
Upper limits on safe lead levels in blood are $10 \frac{\mu g}{100g}$. Blood density is 1060 $\frac{kg}{m^3}$ with average adult having $5L = 5 \cdot 10^{-3} m^3$, meaning that $m_{blood} = 5 \cdot 1.06 = 5.3$ kg. Then the upper mass of lead in blood is $m_{Pb}^{\text{safe}} = 5.3 \mu g = 5.3 \cdot 10^{-9}$ kg. The safe does of polonium meanwhile is $m_{Po}^{\text{safe}} 6.8 \cdot 10^{-15}$ kg. Relation between lead and polonium is thus $\frac{6.8}{5.3} \cdot 10^{-6} = 1.28 \cdot 10^{-6}$.
Radioactive decay is exponential and respects the following equation.
$$ N(t) = N_0 \cdot 2 ^{- \frac{t}{t_{1/2}}} $$
The molar mass of lead produced from polonium is exactly $206 \frac{g}{mol}$, while polonium isotope has $210 \frac{g}{mol}$. This is close enough to disregard.
$$ 1.28 \cdot 10^{-6} = 2 ^{- \frac{t}{t_{1/2}}} \iff t = 13.56 \cdot t_{1/2} = 1876 \text{ days} = \text{5 years, 3 months and 1 week} $$
Which is not even that long. However, it is long enough to consider decontamination.
Active decontamination
There is an interesting article about one famous polonium contamination cleanup in 2006 in the UK.
The obvious solution is to dismantle contaminated objects, dig a waste pit, and dispose of everything there. However, for solid surfaces, other two methods were used.
- Decontamination agents
- Source sealing
The first method refers to chemical agents that extract polonium from hard-to-reach places to be removed with the agent later. They could be quite advanced and as the power armour wearer returns from deployment it is reasonable to assume that decontamination could be up to a full submerge of the thing into a vat with the agent.
The second method uses the fact that alpha particles are easily stopped by matter. For example, a new coat of paint. Solid surfaces benefit mostly from this method.
Lastly, the most compelling reason why I think that polonium radiation is not a critical hazard is detection. One can detect its presence in dust, liquid, and gas as It emits alpha particles. It is very easy to find it if you know what you are looking for as, usually, alpha particles travel a few centimeters in the air.
Environmental specifics
All the points until now apply universally, but this power armour lives in a setting that includes space exploration. I am actually quite positive that these suits are forbidden to use on Earth's surface and whoever uses them could face nuclear retaliation.
Even if they are used though, five years is not that long. However, there are other environments in the solar system. Please, bear with me through some setting details and skip until the conclusion at the bottom if you are not interested.
Mars
Mars is colonized locally, all humans live in seven enormous cities ranging from 70M
population at Argyre Planitia to 127M
population at Noctis Labyrinth.
They are pressurized and their interior water and air are carefully monitored and recycled. They mine and process their own ores and ices to be mostly self-sufficient and, honestly, I designed the power armour to precisely allow their assault.
The power for the cities comes from ITER-style fusion reactors and this by itself makes polonium unlikely to pose a significant challenge. Neutron irradiation of reactor materials is an ever-present hazard and their safe storage is of critical importance. Accidental contamination of water, food, or air must be detected as soon as possible to stop the spread in the early stages.
Furthermore, vast distances between cities are not traversable. The only means of conflict for them are ICBMs and orbital assaults. Each city has nuclear capabilities and that implies fissile reactors which facilitate radioactive leak monitoring and means of decontamination.
Asteroids, stations and spaceships
Space is quite radioactive. Thus radiation level monitoring is vital and it is improbable for polonium particles with their alpha emission to be undetected past the airlock. There is initially no air to stop them there.
The space stations themselves are very cleanable and if a battle took place there, decontamination might be as easy as a new coat of paint.
After all, if boarding took place, it is unlikely that much of the vessel is still pressurized.
Galilean moons
Io is a powerhouse of the Jovian system: geothermal power and available elements fuel asteroid forges and shipyards on Europa, promote food growth on Ganymede, and feed research efforts on Callisto. However, it is worth remembering that Io is a radioactive hell. If one can survive that, polonium is also manageable.
Closing thoughts on radiotoxicity
Overall, radioactive contamination could be a great hazard and should not be underestimated. Especially if it reaches food production or water sources. However, I believe that space colonisation is not possible without robust methods of radiation management and that implies contamination tolerance of extraterrestrial habitats.
Sure, spilled polonium is a very deadly substance, but it is possible to isolate it and decontaminate. There is no biosphere in space where it could propagate until it fully decays. I also like because it highlights the price of waging a war in space
Conclusion
There are several candidates for practical fuel sources for power armour.
- Accumulators
If no additional power source exists within power armour then with a consumption of 5kW the wearer would need more than half a ton worth of accumulators for a 24-hour mission.
- Hydrogen fuel cells
The fuel cell itself is all right, but the hydrogen needs to be pressurised to store energy efficiently. This is undesired, as pressurised gas could explode the wearer if damaged. Furthermore, if a 24-hour mission is assumed, then over 500 liters of modern hydrogen fuel is needed. One can compress them further, but this increases the structural vulnerability of the armour.
- Modern RTGs
Not enough power generation
- Polonium RTG with lithium coolant
Energy output is comparable with accumulators but with no capacity constraints. The only issue is the low efficiency of heat-to-electricity conversion. This requires very effective cooling system. Water is too ineffective, so lithium is chosen. For the 24-hour mission armour needs to evaporate 43kg of lithium. Polonium radiotoxicity hazard is limited due to natural resilience of extraterrestrial habitats to radioactive contamination.
Furthermore, if one looks at potential improvements for the above technologies, certain asymmetry could be noticed.
- Accumulators could always be assumed to improve. To be fair, this whole thing could be avoided by just handwaving in their direction, but what's fun in that? For example, Li-air with its demonstrated $W_{se} = 1.7 \frac{kWh}{kg}$ specific energy.
- Fuel cells are good, but their efficiency is already quite high. Around 40% it seems, the fuel could be different though, but that's a whole other story.
- Modern RTGs are inefficient. With a thermal-to-electrical efficiency of around 6%, they are roadblocked by thermoelectrical elements. Materials with low thermal and high electric conductivities are hard to make with today's technology. Thus, with better material science it is possible to increase their performance dramatically. This will reduce their coolant needs, and make them more compact due to reduced fuel demands.
Overall, it seems like a polonium RTG option is the way for power armour.
The question
Could it work in a hard sci-fi setting or does this sound ridiculous and I am too far into the rabbit hole to notice?
Edit: The answers I aim for are about validity of the logic and technical assumptions above. For example, if there is some technical limitation for lithium evaporation that I have missed, or that polonium boils regardless of the salting used, or that logistics for breach crew with this tech is impossible. The best answer is the one that shows the biggest hole in the power armour design.
Also, I would really appreciate any feedback regarding the whole napkin math I did.
$^1$: Any sufficiently advanced technology is indistinguishable from magic.
$^2$: There is $^{208}Po$ which has half-life of 2 years. It might be a better candidate for fuel instead of $^{210}Po$. However, so little information is available about it, that I just gave up.
Note: It is possible to make the thermal power adjustable, with altered heat source design.