The 30 hour requirement is the stickler. For an earth sized planet this is very close to the Roche Limit. Get too close and the tidal forces are bigger than the gravitational forces and you end up with a disk of gravel.
Tidal force is an (inverse) 3rd power law. Distances and masses are sensitive.
Robert Forward wrote two books, Roche World and Return to Roche World about such a binary.
Note about geometer: Both planets will have a normal day -- there is no permanent dark side. However the hemispheres facing each other will in effect have a much shorter day. The other planet will be at a distance of somewhere around 40,000 km and so will present about a 25 degree disk. This will provide a daily 2 hour eclipse at the equator,getting somewhat shorter as you move poleward.
This assumes that the plane of their mutual orbit is the same as the plane of the orbit. If it's tilted, as is the earth/moon system then the eclipses will vary through the year. While this can be calculated, you may do better to make a scale model of the two planets, and play with a flashlight.
Multiparagraph response to Bob.
@BobDylan A single planet can be tidally locked to its star, much like the moon is to the earth. For decades we thought that Mercury was one such planet. If it has an atmosphere, you get huge convection from the front face to the back face, and hurricane winds from the back face at the surface.
Two planets cannot both be locked to the primary while orbiting each other. They will lock to each other instead. Tidal force from a nearby planet is much stronger than the tide from the star.