We've discovered stars that are contact binaries. This means that they orbit so close together that their photosphere reaches through their Roche lobes and links the two stars together.

Contact binary pair

This started me thinking about the possibilities with respect to gas giants though, could in theory gas giants orbit each other also so close together that their atmospheres merge? Would they be able to hold together in that state or would they rip each other apart?


3 Answers 3


Probably not.

A direct quote from here would be nice, but I'm not sure if there's any relevant copyright on the text, so I'll just summarize. Here are the steps to forming a contact binary star system:

  1. A binary star system forms
  2. After billions - perhaps only millions, in larger stars - of years, one of the stars becomes a giant.
  3. The giant grows and grows until its outer layers reach its Roche Lobe.
  4. One of two things can happen: If the other star, too, is large, the stars may quickly form a contact binary. If the other star is small, matter transfer from the larger star to the smaller star may take place and then a contact binary may form.

Here's why I don't think this could happen in planetary systems:

  • Planets don't grow much once they become full-fledged planets. They can shrink and release energy via the Kelvin-Helmholtz mechanism, but they generally can't grow. They can grow when they're in the protoplanet stage, or when they've just reached planethood - whenever that happens - and are still accreting excess material
  • Gas giants generally collect all the gas in their immediate area. This means that its more likely that one will form first and take all the gas from another . . . unless matter transfer happens, as detailed above.
  • There are a lot of collisions among protoplanets. It's unlikely that two massive planets will form near one another without colliding. They'll each have sustained collisions with other protoplanets and planetesimals; I would think these collisions should make them be at a higher risk for collision with each other.
  • Gas giants often migrate from the outer reaches of the stellar system, so in their early days, their orbits may be unstable.

Maybe a temporary common envelope could form at some point, though the system would be unstable.

We can calculate the approximate radius of the Roche lobe. Let's assume that the planets are both the same mass, so $M_1=M_2$ and $\frac{M_1}{M_2}=1$. Given the distance between the planets to be $A$, the radius of the Roche Lobe $r_R$ is $$r_R=\left(0.38+0.2 \log \frac{M_1}{M_2} \right) A$$ $$r_R=(0.38+0)A$$ $$r_R=0.38A$$ Let's say that the gas giants are just large enough and close enough that they reach the outer edges of their Roche lobes. We'll also say that they are about the same mass and radius as Jupiter. $$r_R=r_J=0.38A$$ $$A=2.61R_J$$ That's problematic, because we can also calculate the Roche limit of the planets - the point at which one will be torn apart by the other. In this case, the more massive of the two has a mass $M_p$, and the less massive has a mass $M_2$. $$d=1.26 R_J \left(\frac{M_p}{M_s} \right) ^{\frac{1}{3}}$$ $$d \approx. 1.26R_J$$ So they're way to close! The more massive one will tear the less massive one apart - in essence, they'll collide.

Regarding what TimB wrote in the bounty - I don't have the expertise necessary to do an analysis like that, so I'll leave that to someone else. I wouldn't be able to do it as well as it deserves.

  • $\begingroup$ Wouldn't they have to orbit each other as well? $\endgroup$
    – bowlturner
    Jan 17, 2015 at 15:10
  • $\begingroup$ @bowlturner The gas giants? Yes. Here, we'd be looking at a very short period. $\endgroup$
    – HDE 226868
    Jan 17, 2015 at 15:12
  • $\begingroup$ Does the Roche limit behaviour change because they're gas giants though? There isn't really anything to tear apart since the cores are much further apart - they just end up sharing a common atmosphere. $\endgroup$
    – Tim B
    Jan 18, 2015 at 12:40
  • $\begingroup$ @TimB Hm. I don't know what would happen in that scenario. If the cores were within each other's Roche lobes, then one would be torn apart. I'm not sure what will happen here. $\endgroup$
    – HDE 226868
    Jan 18, 2015 at 18:08
  • 1
    $\begingroup$ You can quote from anything you want. That would not be a copyright concern as it was definitely fall under "fair use". $\endgroup$ Mar 15, 2015 at 6:55

I am really not 100% sure on my math here, but I think it checks out:

Using HDE's numbers:



It seems logical to me that the cores will be outside their partner's Roche limit if the radius of each core is <= 2.61 - 1.26 * 2 = .09RJ * 2 = .18RJ.

Estimates of Jupiter's Core put it at 4-14% of Jupiter's Mass. Let's go with the 4% number because we're just seeing if this is feasible. If we assume the core is average with the mass of Jupiter, then it would need to be about .26RJ - so way big.

From here we should be able to calculate the minimum mass needed of the core (more mass = smaller in radius) for the cores to be outside the Roche radius. Unfortunately I need to head to dinner so I can't finish it up right now, I'll try and get some pen and paper later and work through the formulas. I don't think it's looking good though, the core would need to be really massive to get under that .18RJ.

  • 1
    $\begingroup$ This answer seems to be heading in the right direction to get the bounty but as you say is incomplete right now. I don't suppose you are able to finish it before the bounty expires? $\endgroup$
    – Tim B
    Mar 10, 2015 at 8:12

While HDE 226868 has a bunch of reasons against them I don't think they add up to a total showstopper.

As he says, they can't form near each other--but that doesn't preclude a binary pair from a capture event.

Now suppose the capture ended up with a retrograde--they'll spiral in due to tidal forces. At some point you'll end up with a contact binary. Soon after that they go splat.


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