Dry ice sublimates absorbing $573.02$ $kJ/kg$ and has a density of $1870$ $kg/m^3$.
You have produced $2$ $m^3$, they weight $3740$ $kg$, and absorb $2.1$ $MJ$ while sublimating.
Assuming your lake is at an average temperature of $15$ $C$, the mass of dry ice will be able to lower to $0$ $C$ the temperature of about $60$ $kg$ of water, barely $60$ liters. Since you talk about lake, and not pond, your mass of water will be way bigger.
The net result of your dry ice bombing will be a somehow cooler water and a lot of fog.
About the dry ice, producers advise to transport it in non sealed containers (so remember to open the venting valve of your bomber), and since it sublimates at a rate of 10% every 24 hours, to transport it immediatly before usage (I think this is your case).
Once the dry ice splash on water it will initally break down in smaller parts, rising some waves on the lake surface. Then, since the solid is denser than water, it will sink to the bottom of the lake. During the sinking it will sublimate thanks to the heat transferred from water.
From the surface this will be visible as a big boiling, as the gas will start flowing out of the liquid. Together with the gas, a dense fog will start to cover the surface of the lake.
For a reference, see this video.
The main concern it would not be about the visibility, but about the effect of gas on living beings. CO2 displaces oxygen from air, in this case from the ground level, therefore any animal out of water risk to suffucate due to the presence of CO2 at higher concentrations.
Something similar has happened in the past at lake Nyos:
In 1986, possibly as the result of a landslide, Lake Nyos suddenly emitted a large cloud of CO2, which suffocated 1746 people and 3500 livestock in nearby towns and villages
Provided there is a decent ventilation (which around a lake should be almost granted) the local excess of CO2 will be dispersed within hours, and its level will fall below deadly concentrantion accordingly.