In its wandering through the Milky Way, the solar system is getting close to a solitary neutron star. The neutron star will "fly by" above the plane of the ecliptic and its closest distance from the Sun will be 10 AU. The neutron star belongs to the Milky Way too, therefore its orbital velocity is comparable to that of the Sun: they cross each other path.

How and when could we possibly detect the neutron star during its approach? We have our present technology.

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    $\begingroup$ How fast will this happen? Recently I had (really interesting) talk with astronomer who was really worried about Milky way colliding with another galaxy.... Because it will happen "pretty soon"... In other words, in 65 million years $\endgroup$ Feb 24, 2017 at 12:24
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    $\begingroup$ For an extremely/excruciatingly detailed example, check out the first part of Robert Forward's “Dragon's Egg”. $\endgroup$
    – pablodf76
    Feb 24, 2017 at 14:06
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    $\begingroup$ @PavelJanicek If it is the Andromeda galaxy the astronomers were talking about, that won't happen for another 4 billion years. Though the collision is inevitable, I would say it is less of a collision and more of a merger. There will be lots of gravitational changes as the two merge but there will be little to no actual collisions. $\endgroup$ Feb 24, 2017 at 15:02
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    $\begingroup$ Ok, if their orbital velocity is comparable, they shouldn't "cross paths" since they are going approximately the same direction at the same speed. Stars don't wander, they orbit. Even if it is moving at a very high relative velocity, it's going to take thousands of years to transit the solar system from one edge of the oort to the other. And, as one of the answers stated, it would destroy the solar system. $\endgroup$
    – Seeds
    Feb 24, 2017 at 16:27
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    $\begingroup$ The fortunate thing with stars is that they're quite tiny compared to interstellar distances. Our sun has a diameter of 1.47E-7 light-years and the nearest star to our sun is 4.37 light-years distant. If they were spaced a meter apart, the sun would be a particle ~37 nm in diameter. This is on the order of magnitude of a small virus particle. Combine this distance scaling with the low density of stars and interactions should be extremely rare. For extra fun, the earth would be a particle ~308 pm, which is roughly the bond length between two Helium atoms in He2. $\endgroup$
    – Dan Bryant
    Feb 24, 2017 at 18:11

4 Answers 4


Depends on the type of the neutron star

Neutron stars that can be observed tend to put out lots of energy. Pulsars in particular would be pretty easy to spot from literally a galaxy away. Young neutron stars may not yet have developed into pulsars, but would still be powerful x-ray sources. However, if a neutron star is young, then it is likely embedded in the cloud of its supernova, which would be another pretty big giveaway that there is a neutron star around (other than the massive x-ray source). In any case, a neutron star shouldn't be able to hide for long.

If a neutron star couldn't be detected (for some reason)...

The solar system would be thrown into chaos.

A neutron star will have a mass greater than the Sun, and up to 3 solar masses. Therefore, its gravitational attraction will be greater than the sun at the same distance.

The semi-major axis of Saturn is 9.5 AU, Uranus is 19.2 AU, Neptune is 30.1 AU. Thus, if a neutron star passed 10 AU above the plane of the ecliptic, it would be exerting more gravitational pull on those planets than the sun. I don't know exactly what would happen, but its a safe bet by the time the neutron star passed, there would be no more planets in the solar system.

Given this, the advance warning of an un-detecatable neutron star (which is basically a black hole) would be the objects of the Oort cloud and then Kuiper belt being flung willy-nilly throughout the solar system and out into the galaxy. A massive increase in comets would certainly be detectable to even amateur astronomers. Who says comets aren't harbingers of doom!

  • $\begingroup$ Third giveaway would be gravitational lensing, wouldn't it? $\endgroup$
    – Mołot
    Feb 24, 2017 at 16:31
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    $\begingroup$ Yes, as long as it passed between Earth and something that gets looked at enough to notice the lensing. $\endgroup$
    – kingledion
    Feb 24, 2017 at 16:34
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    $\begingroup$ I'd like to point out that the solar system would be thrown into chaos regardless of whether we noticed or not: at least, restricting ourselves to current technology! $\endgroup$
    – jpaugh
    Feb 24, 2017 at 20:03
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    $\begingroup$ @jpaugh When Earth gets flung into interstellar space, I think even the cave men would notice. $\endgroup$
    – kingledion
    Feb 24, 2017 at 20:06
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    $\begingroup$ I see I misread your heading. I thought you were implying that we could actually prevent the chaos if we noticed in time. $\endgroup$
    – jpaugh
    Feb 24, 2017 at 22:01

A dead neutron star could probably be detected long before it entered the solar system. Before the general consensus was reached by cosmologists on modern cold dark matter and dark energy cosmology, a viable candidate for dark matter making up galactic halos were known as MACHOs: Massive Astrophysical Compact Halo Objects. Neutron stars are one of the prototypical examples of a macho.

MACHOs in general don't emit enough light, radio, or x-ray to be detected directly, but because they are so compact, they can be detected by gravitational microlensing of background stars as they transit in front. The Wikipedia article on MACHOs has a decent summary.

EDIT: I don't have enough rep to comment yet, but to address the question of transit time:

The sun's peculiar motion (i.e., it's motion relative to the average rotational velocity of the local segment of the milky way) is about 13 km/s reference . The neutron star could easily have a similar order of magnitude, so let's call the relative crossing velocity 20 km/s. From wikipedia, the solar system is about 50 AU in radius, so about 15 billion km in diameter. This gives a transit time of about 20 years.

  • $\begingroup$ I think this is the correct answer. $\endgroup$
    – Gray Sheep
    Feb 24, 2017 at 17:32
  • $\begingroup$ You can “comment everywhere” now, thqnks to the rep you gained from posting this. So, you can move your remarks to where you really wanted them, or just better integrate with your Answer. $\endgroup$
    – JDługosz
    Feb 25, 2017 at 13:35
  • $\begingroup$ The Kuiper Belt is about 50AU, the Oort cloud is 50 000 - 200 000 AU $\endgroup$
    – Seeds
    Feb 27, 2017 at 17:27

It will be terribly easily detected IMMEDIATELY.

There could be 3 or four possible types/stages of a neutron star. A pulsar or magnetar would be immediately detected far, far before it reaches 10 AU to the sun in any direction. The magnetic field would be so powerful, it will probably affect all the magnetically sensitive devices on Earth, considering their magnetic fields are hundreds of billions of times stronger than the magnetic field of any planet in our entire solar system.

If it is an active neutron star, with powerful gamma bursts, we might never detect it at all: we would all be dead already. This would happen if Earth is unlucky enough to be in line with the poles of the neutron star.

Even if it is a dead neutron star, no longer having the unimaginably powerful magnetic field or surface temperature of billions of degrees, it would still be immediately detected due to its extremely strong and devastating effect on the planets in our solar system. Considering that the mass of a neutron is 1.4 to 4 times the mass of our sun, it will absolutely wreak havoc at 10 AU from the sun. The orbits of the planets will initially be elongated irreparably, and then some of them might go swirling into the neutron star, or get slingshot out of the entire solar system.

At the very least, the orbits of the middle planets (Jupiter, Saturn) would be irreparably elongated. Before getting to 10 AU, the neutron star will wreak disaster on the objects in the Kuiper Belt and far, far before that, it would pick up a whole gang of Oort Cloud comets and planetesimals, bringing them inwards with it. Long before the neutron star reached 10 AU, the comets and planetesimals of Oort Cloud and Kuiper Belt will be raining down on the planets (including Earth).

We would probably all be extinct several years before the neutron star reached 10 AU from the sun. So in a sense it would be impossible to detect the neutron star entering our solar system.

In response to Morning Star's comments

I am not sure that the magnetic field would be so strong. Yes, it is extremely strong on the surface. But it decreases cubically with the distance. I think it may be a similar misunderstanding as it goes with the black holes: yes they have a very strong gravitational field, but an 1 Solar mass black hole from 1 AU would have the same gravity as the Sun.

You might not be sure that the magnetic field would be so strong, but a quick internet search tells me otherwise. Try this:

These magnetic fields are hundreds of millions of times stronger than any man-made magnet, and quadrillions of times more powerful than the field surrounding Earth. - Reference

In order to stay on the safe side, I refrained from quadrillions of times and stayed with hundreds of billions of times. About the gravity of black holes, where did I claim that a black hole of mass $x$ will ever have a gravitational field more massive than that?

The change on the orbits of the outer planets would be easily visible and permanent, but it wouldn't have a major effect to us.

In fact the inner planets would be affected more severely by the gravity of the neutron star. It is simple pythagorean theorem scenario calculating the distance of the intruder to the planets. Here, let me help you:

enter image description here

Try and work out the relative distance of the planets from the neutron star and figure out which ones would be affected more.

Furthermore, the neutron star's gravity and the sun's gravity will partially assist each other, not only pulling the planets out of the solar system's plane, but also bringing them closer toward the sun. It is a matter of trignometric ratios and angles. Work it out.

About the gamma bursts: Not all neutron star produces gamma bursts and even they don't do it always.

Where did I state that all neutron stars produce gamma bursts? And when did I state that a GRB source remains active for a long time? Here, I am quoting myself to help you better understand what I meant: If it is an active neutron star, with powerful gamma bursts, we might never detect it at all: we would all be dead already. This would happen if Earth is unlucky enough to be in line with the poles of the neutron star.

The meaning of my statement(s) becomes clear now. Yes?

The surface temperature of the neutron stars is some hundreds of thousands, at most some million K, and not billions. Which is still high, but their whole radiation is not catastrophic. It wouldn't be surely visible with free eye.

Let me help you about the surface temperature of neutron stars. Here: "The temperature inside a newly formed neutron star is from around 10$^{11}$ to 10$^{12}$ kelvin. However, the huge number of neutrinos it emits carry away so much energy that the temperature of an isolated neutron star falls within a few years to around 10$^6$ kelvin." - Reference

OP never mentioned that the neutron star entering the solar system is an old, cold one. Once again I refrained from stating trillions of degrees and stayed on the safe billions figure. Furthermore, notice that even after losing most of their heat, neutron stars still get to a temperature of about a million, an order of magnitude greater than "hundreds of thousands".

Also, where did I state that all of the radiation of the neutron star would be disastrous for us/living beings? And where did I ever mention that all the electromagnetic radiation spectrum of a neutron star lays in the visible range? Quote me.

A 4 solar mass neutron star from 10 AU has the gravitational force of 1/25 of the Sun. Of course it perturbs the orbits, but not significantly, in the case of the Earth it may be even survivable. Considering that the OP says the NS will go above the elliptic, the majority of the orbit perturbation will change the plane in which the Earth orbits. This part won't affect the weather on the Earth. The remainder, yes.

As I mentioned earlier, considering that the intruder star and sun are not perpendicular from the reference point of Earth, they will have a combined gravitational effect on all the planets, pulling them up (as in, away from the solar system's plane) AND toward the sun.

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    $\begingroup$ Comments are not for extended discussion; this conversation has been moved to chat. Additional note to all involved: Please do not get confrontational during discussions and please do not abuse flags. Just because you disagree with someone does not make their criticisms offensive or not constructive. $\endgroup$
    – HDE 226868
    Feb 25, 2017 at 2:31
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    $\begingroup$ Let us continue this discussion in chat. I would love to know more detail, but instead of dragging it in the comments section, lets talk in the chatroom :D @LorenPechtel $\endgroup$ Feb 25, 2017 at 17:35
  • $\begingroup$ @L.Dutch Note that Loren Pechtel has been nice enough to run several simulations about the scenario. While they agree with me about the radiation and chaos in Oort Cloud and Kuiper Belt regions, the gravitational effects of the intruder will vary widely, depending on the mass of the entering neutron star. While I am honored that you accepted my answer, I think kingledion's answer is much better than mine and deserves to be accepted. My answer has a few errors about the gravitational effects of the neutron star, as Loren Pechtel has updated me. $\endgroup$ Feb 27, 2017 at 14:21
  • $\begingroup$ <scribbles "image not to scale" on the lower corner.> $\endgroup$ Jun 15, 2017 at 13:39

First, it's important to realize how very unlikely this is. Even coming as close as Neptune the odds are many millions to one against in a million year period, and billions to one against in a thousand year period. After all, neutron stars are much rarer than stars, or white dwarfs, because only the very heaviest stars can becoem neutron stars.

Debunk: Our Sun or Earth could be hit by a rogue planet, neutron star, black hole, brown dwarf or star

So, this is rather theoretical. But if this is for some science fiction story, a young neutron star or one in a binary system would be easy to spot from its X-ray emissions and likely to be a pulsar too. But unlike white dwarfs, neutron stars can cool down and become dead remnants.

Still we'd detect it via gravitational lensing of distant stars especially if it moves in front of the denser parts of the Milky Way in the sky.

You are also talking about something heavier than our sun, so it would have a significant effect on other objects in the solar system and we have many of those now that we are monitoring, transneptunian objects as well as several distant spacecraft that we are still in contact with (Voyager I and II, Pioneer I and II, New Horizons). After all, the gravitational attraction would be more than that of our sun for an object equidistant from both.

Also, objects from the Oort cloud would likely hit it from time to time, and cause flashes of light as they hit its solid surface, and most likely leave an accretion disk. I'm not sure how often that would happen or how easy it would be to detect, if anyone knows how to work it out do comment!


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