Whoa whoa whoa, did I just hear a 'no heating' in there? I see these coil guns have a thermodynamics compensator!
The second law of thermodynamics states that entropy is always increasing, or from a practical engineering point of view, every process generates waste heat. In a coil gun the waste heat will come from resistance to the current in the coils according to $P = I^2R$. Since the current term is quadratic, even with a very low resistance, a very high current (i.e. a very powerful Gauss gun) would still produce appreciable waste heat.
I couldn't find a lot of hard numbers on energy efficiency for coil guns. Rail guns seem to be more popular with governments (specifically the US Navy) for funding. Rail guns, to be sure, have huge cooling problems, but I can't find similar statements about coil guns. Here is a possibly legitimate website talking about trying to get coilgun electrical efficiency up to 26%. That means that 26% of the electric current drawn is converted to projectile kinetic energy; which implies that the other 74% becomes entropy.
So, in conclusion, the coilguns have heat problems too. So for a certain application where high rate of fire in short bursts is desired (point defense weapons, specifically), a Gatling gun design has advantages over active cooling due to its low cost and mechanical reliability.
Edit for more maths
Greybody power radiation from the Stefan-Boltzmann law is $$P = A\epsilon\sigma T^4$$ where $P$ is the radiation power in watts; $A$ is effective surface area (i.e. facing away from the object so emissions are not reabsorbed); $\epsilon$ is emissivity; $\sigma$ is the Stefan-Boltzmann constant; and $T$ is temperature.
Since we want maximum heat disspiation at high temp, assume we can find a gunsteel alloy with emissivity of 0.9 and excellent strength at the desired operating temperatures of no more than 1200$^\circ$K. Assume effective surface area of 1 m$^2$ and we get $$P = 1 \text{m}^2 \cdot 0.9 \cdot 5.67\times10^{-8} \frac{\text{W}}{\text{m}^2\cdot\text{K}^4}\cdot (1200)^4 \text{K}^4 = 105 \text{kW}.$$
Assume that our gauss gun is 80% efficient so 105 kW of waste heat correlates to 26 kJ of muzzle energy per second. If you fired a 0.1 kg projectile (twice the mass of a .50 bullet) you would get muzzle velocity of $26000 J = \frac{1}{2} 0.1\text{hg} \cdot v^2$, $v = 721 \frac{\text{m}}{\text{s}}$.
So it is feasible to cool by radiation a 6 barrels * 1 round / sec * 60 sec / min = 360 rounds/min, 26kJ muzzle velocity Gatling gun.