The average equilibrium temperature can be obtained from the Stefan-Boltzmann law, for your data 293.5 K (20 C). Compensating for the Earth-like atmosphere, (+15 K for Earth, closer to +12.5 K for this planet), we have an average temperature of approximately 306 K (33 C). Quite hot, as expected from a higher solar flux, and smaller albedo.
Another useful average we can get from this law is the equatorial average, 311 K without the atmosphere, ~323 K compensated.
Equations for temperature estimations without an atmosphere:
Effective influx: $= solar flux * (1-albedo)$
Global average $= \left(\frac{I_e}{4\sigma}\right)^{\frac{1}{4}}$
Equatorial average $= \left(\frac{I_e}{\pi \sigma}\right)^{\frac{1}{4}}$
Stationary sun-in-zenith average $= \left(\frac{I_e}{\sigma}\right)^{\frac{1}{4}}$
Where $\sigma$ is the Stefan-Boltzmann constant ($σ = 5.67×10^{-8} W m^{-2} K^{-4}$), and $I_e$ is the effective influx.
For a rapidly rotating planet, use the equatorial average for the equator temperature, for a very slowly rotating planet, use the sun-in-zenith equation for the peak temperature. For a case in between those extremes, use something in-between those equations.
Your planet seems to be divided into two regions, a lowland and a highland. We find the highest temperature variations on the equator part of the highland, where a necessary low cloud cover gives huge, desert-like variations, reaching almost 90 C shortly after noon (actually 130 degrees C if we calculate the black-body equilibrium, but we must compensate for atmospheric convection), and less than 0 C degrees (perhaps as low as -15 C) shortly before dawn.
In the lowland, the atmosphere, combined with clouds formed by the lakes ,gives more inertia to the system, thereby limiting the variations. (0 - 50 degrees C).