IT seems that the binary planet system you described would have a much shorter day than you describe.
The sizes and distances of he two planets.
Earth has a mean radius of 6371.0 kilometers and thus a mean diameter of 12,742 kilometers. Four times that is 50,968 kilometers center to center.
Each planet is approximately 85% the diameter of Earth, 62% as massive, with 85% the gravity. The atmosphere is about 50% thinner than the Earths.
So each planet would have the 0.85 diameter and radius of Earth. Each planet would have a radius of 5,415.35 kilometers, And so the distance between the surfaces of r the planets would be 50,968 minus 2X 5,415.35 kilometers, or 40,137.3 kilometers.
Part Two: Surface Gravity and Escape Velocity.
According to this online surface gravity calculator, https://philip-p-ide.uk/doku.php/blog/articles/software/surface_gravity_calc each planet would have a surface gravity 0.85 that of Earth.
I note that it would be rare for a planet to have an escape velocity and a radius with the same proportion relative to that of Earth.
But the escape velocity, and not the surface gravity, of a planet is the important factor for the planet retaining an atmosphere. No description of the properties of a fictional planet is complete without listing the escape velocity.
Here is a link to an online escape velocity calculator: https://www.calctool.org/astrophysics/escape-velocity
According to it each of your planets should have an escape velocity of 9.553 kilometers per second. That is 0.854 of Earth's escape velocity of 11.186 kilometers per second. There is a noticeable difference in the ratio of the planet's escape velocity relative to Earth and the ratio of its surface gravity relative to Earth. In many cases the difference between the ratios would be much greater.
So the surface gravity of a world and the escape velocity of that world have to be calculated separately, and they should never be described together as it's "gravity".
Part three: The Orbital period.
So what about the orbital period of the two planets? Would it be eight days? To me eight days intuitively seems too long.
According to this online orbital period calculator: https://www.omnicalculator.com/physics/orbital-period
A binary system with two planets each with 0.62 the mass of Earth and a semi-major axis of 50,968 kilometers would have an orbital period of 1 day and 4 hours.
A binary system with two planets each with 0.62 the mass of Earth and a semi-major axis of 100,000 kilometers would have an orbital period of 3 days and 6 hours.
A binary system with two planets each with 0.62 the mass of Earth and a semi-major axis of 200,000 kilometers would have an orbital period of 9 days and 6 hours.
A binary system with two planets each with 0.62 the mass of Earth and a semi-major axis of 175,000 kilometers would have an orbital period of 7 days and 13 hours.
A binary system with two planets each with 0.62 the mass of Earth and a semi-major axis of 185,000 kilometers would have an orbital period of 8 days and 5 hours.
So you should be able to calculate a system with either the separation of 50,968 kilometers or an orbital period of f8 days, but not both.
Part Four: The Distance from the Star.
The planets orbit their F0 star once every 3 years, at a distance of 2.5 AU. Axial tilt and eccentricity are near zero, so they do not experience seasons the way that Earth does.
An F0V class star should have luminosity 7.24 that of the Sun. So the Earth Equivalent Distance, or EED, where a planet would achieve the same amount of radiation from the star as Earth gets from the Sun would be the square root of 7.24 times 1 Astronomical Unit (AU). The square root of 7.24 is 2.69. So the EED of a F0V star should be about 2.69 AU.
At a distance of 2.6 AU from the star, the planets should receive about 1.037 as much radiation as Earth gets from the Sun. So the problems with ultraviolet radiation mentioned in Corey's answer would be stronger than if the planets were at the EED or father from the star than the EED.
These are my observations about the astronomical set up of the system.