There is no effective air defense possible!
As long as the mages can use the line of sight, they can outfly any ground gun of the civil war era. They just fly above the cannon reach and are impervious to small arms. But what is the cannon reach?
maximum air defense hight
Well, the various field artillery pieces shoot between 1000 and 2800 yards at $\theta=5°$ elevation with muzzle velocities of 1000 to 1500 feet a second. Its velocity downrange will stay persistent, and its velocity up gets reduced by the acceleration downwards from earth attraction, this drawing an arc. All we need now is the muzzle velocity and we can calculate the shooting height technically we don't even need the downrange reach! So, let's plot the time it takes to get to the highest point. $$0=v_{0}\sin\theta-g*t$$ $$v_h=v_0\sin\theta$$ $$t=\frac {v_h}{g}$$
Injecting the fastest shooting gun there, the 12 pounder Whithworth at 5° with $v_0=\pu{475.2 m/s}$ and $g=\pu{9.81 m/s²}$, we get a time of $t=\pu{4.22 s}$ until its apex - which we can plug into the location formula for the shot. also, just for the test, let's plug the 5° where we know that it should be about $$y=\frac {v_h^2} {2g}=\pu{87.42 m}$$ But it also points to a different problem: that gun should in theory have a range of 11.5 kilometers at that elevation, but it only has a reach of about 2.5 kilometers... where is the rest of the energy going?! Wind resistance. We completely ignored wind resistance! So let's fix the formula, add drag coefficient $C=0.47$ (even though that is for a sphere and the projectile is more complex shaped) and a diameter of 2.75 inch or about $d=\pu{70 mm}$, air density $\rho=\pu{1.225 kg/m³}$, mass $m=\pu{5.4 kg}$ and thus $r=\pu{0.035 m}$. $$a_{drag}=\frac 1 m C \rho r² v²=\pu{0.00013061 m}\times v(t)²$$
This can be plotted! Let's see...
$$y=v_0\sin\theta t- \frac 1 2 (g+a_{drag}) t² $$
$$x=v_0\cos\theta t- \frac 1 2 (a_{drag}) t²$$
Now... with a bit of oversimplification (pinning the speed for the drag calculation) our flight times are different. For $\theta=5°$ the projectile only get 65 meters above the battle and impacts after 6.7 seconds. It also gives us a reach of 3114 meters, which is the actual range while the 2.5 kilometers is the effective range - as in, you shoot at targets at that range because you want to hit about chest-high.
Now, let's turn that gun to 35° (the maximum the gun allows) and shoot... the projectile reaches its apex after about 10.15 seconds at 1400 meters off the ground. Or almost a mile.
If our engineer invents a mounting that allows shooting straight up, then the gun even can reach a height of about 2800 meters, close to two miles in height - with a flight time of 12 seconds to that point.
only low air defense...
Our mages can fly their griffons everywhere there is enough air to breath. That is anywhere below 26000 feet or 8 kilometers. The guns available only can deny the lower 2 miles to the mages and even that very ineffectively. So effectively the mages just fly at 2.5 kilometers high without any chance to hit them at all - and they just need to have either a very basic telescope to hit targets effectively, or just use indiscriminate bombardment of anything that looks like an encampment. But what can you see from that height?
If you fly 4 kilometers like the Italians over Ethiopia. They basically would see the world below in about 1:16000, so to be about 1 millimeter to them, the feature on the ground would be 16 meters wide - or about the size of a building. That's enough to barely make out an encampment while using a 4 times magnification optic allows spotting single vehicles.
Though the mages fly at about half the height, so they spot at double the resolution. They can see single tents easily, vehicles become visible with a 2 times magnification and at 4 times they can see the artillery pieces pretty clearly.
Now comes the nail in the coffin: flight time of the projectile. Assume the mage comes into the range of two kilometers because they want to snipe artillery. The gun fires. The flash of the gun gives away the position, the mage does literally nothing. The projectile reaches the spot the mage was expected to be at a crawling pace (it slows, remember?) and almost against its armor. Annoyed, the griffon smacks the solid slug projectile down towards the gun. It starts hurtling down and impacts directly next to the gun, killing the crew and gun. Or the mage does a tiny turn and the projectile misses by a dozen meters or three. And they can hurl a fireball down the same moment they see the flash and still be safe.
You see, effective air defense is impossible with just that range and reaches of civil war ground guns unless you take to the air yourself. Cannister shot and explosive shells just wouldn't even get close to the height that the 12-pounder Whitworth can reach! Basically, any mage flying above about one mile is impervious to any air defense you could muster with that technology - and those very low flying mages can see individual vehicles clearly by eyesight!