Albedo & Reflectance
Scientists can calculate the amount of solar output Earth receives at a given distance from the sun. Earth reflects some of this light into space, reducing the total radiation absorbed. This effect is described by the term albedo, which is a measure of the average amount of light reflected by an object.
Albedo is measured on a scale from zero to one. An object with an albedo of one would reflect all light reaching it, while at zero albedo, all light would be absorbed. Earth's albedo is about 0.39, but changes over time such as cloud cover, ice caps or other surface features change this value. (Source)
Since you know the albedo, you know how much of the star's light will be reflected. The Moon's albedo is about 0.12, so your gas giant's albedo is 0.48, meaning it will reflect 48% of the light that falls on it. How much that is in lux requires knowing how far the planet is from its star and some specifics about the star, which you haven't provided.
Note: Lux is the amount of illumination when one lumen is evenly distributed over one square meter. In other words, it's a measurement that makes sense to an observer (because distance must be involved)... and the only observers you've mentioned in your question are on the moons. That's kinda an ugly computation since part of it (to be accurate) would need to accommodate the penumbra of both moons. Granted, you're probably trying to determine if the reflected light of the primary can sustain life... but calculating lumens would be a whole lot simpler. Nevertheless, it would help if you explained why you need that measurement. There might be a simpler solution.
Angular Size
The angular size of an object is determined uniquely by its actual size and its distance from the observer. For an object of fixed size, the larger the distance, the smaller the angular size. For objects at a fixed distance, the larger the actual size of an object, the larger its angular size. For objects with small angular sizes, such as typical astronomical objects, the precise relationship between angular size, actual size and distance is well approximated by the equation:
angular size = (actual size ÷ distance)
However, when using this equation you must be very careful about the units in which quantities are measured. If the actual size and the distance are measured in the same units (metres or kilometres, or anything else as long as it is used for both quantities), the angular size that you calculate will be in measured units called radians. A radian is equal to a little more than 57° so, in order to obtain angular sizes in degrees, the following approximation can be used (as long as the angular size is not too great):
angular size = 57 × (actual size ÷ distance) (Source)
Your primary is 1.04X the radius of Jupiter (r = 69,911 km) so the "size" of your primary is 145,414.88 km.
Moon #1 (distance 544,439 km), angular size of primary = 0.267 radians or 15.3° of the sky.
Moon #2 (distance 1,002,864 km), angular size of primary = 0.145 radians or 8.3° of the sky.
Note that I used the first equation and a handy online radians-to-degrees converter for better accuracy. For comparison, Earth's moon has an angular size of about 0.5°. So you have some hefty views.
