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Now, I have a fictional alloy called marbelar in my world, having a similar appearance to brass, featuring a reddish-gold appearance. It also has the highest stopping power out of any material in my world, basically, it makes really good armor. What I'm asking is, what would be the materials used to make it, and how effective would it be? Do note that this is for a space age world, so it pretty much has the entire periodic table at its disposal. Basically, look for a light, durable, and strong alloy.

Update: I have changed marbelar from an actual alloy to a subset of Divinitite, my universe's version of handwavium or unobtanium, making this question irrelevent.

Update 2: I just started my chatroom called The Council Of Devourers, for discussing the creation of my universe.

Update 3: The Council of Devourers is closed now. No further discussion shall occur.

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    $\begingroup$ well you can start by what kinetic energy resistance is. in the real world that would be mass so you are asking what is the heaviest alloy you can make. $\endgroup$
    – John
    Mar 9, 2021 at 22:20
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    $\begingroup$ The word orichalcum has two meanings: first, it is the normal word used in Latin and Greek for what we call in English brass; if your alloy is similar to orichalcum in this (most common) sense, then it is made of copper and zinc. Second, it is used by Plato to refer to an unspecified fantastic metal used by the splendiferous civilization of Atlantis. If your alloy is similar to orichalcum in this (fantastic) sense, then it is obviously made of unobtainium and handwavium. Which is to say, what do you mean when you say that the alloy has "a similar makeup to orichalcum"? $\endgroup$
    – AlexP
    Mar 9, 2021 at 22:26
  • $\begingroup$ @AlexP there is, in fact, a real life form of orichalcum, independent from brass. Orichalcum is a gold-copper alloy, although in what percentages I do not know. $\endgroup$ Mar 9, 2021 at 22:33
  • $\begingroup$ The vast majority of gold jewellery and gold coins are made from a gold and copper alloy. Pure gold is called 24 carats; most jewellery is made of 18 carats gold, that is, and alloy containing three quarters gold and one quarter copper. Gold and copper can be alloyed in any proportion, the resulting color varying from yellow to reddish yellow to yellowish red to red. (That is, any gold-copper alloy with at least one half gold is yellow, or at least faintly reddish yellow.) $\endgroup$
    – AlexP
    Mar 9, 2021 at 22:51
  • $\begingroup$ @AlexP I am looking for a material that is somewhat of an off gold color. Basically, think of a cross between a gold color and a brass color. $\endgroup$ Mar 9, 2021 at 22:53

1 Answer 1

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"I have a fictional alloy called marbelar in my world, having a similar makeup to orichalcum,"

Your Marbelar is obviously make out of sintered Quinzanium, with an alloy of Howbenium and Salvarite plating to secure it.

Seriously: You are asking us for the exact formulation of a Fictional metal, which must be similar to another mythological metal.

I advise you approach the author that invented the Marbelar for their writings, and ask them. And if that person is yourself, then the use of a mirror might be handy.

Here is what wiki has to say about Orichalcum.

Orichalcum has been held to be either a gold-copper alloy, a copper-tin or copper-zinc brass, or a metal or metallic alloy no longer known. In later years, "orichalcum" was used to describe the sulfide mineral chalcopyrite and also to describe brass

That leaves a lot of leeway for wandwaving when making something similar. a lot.

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  • $\begingroup$ Marbelar is actually something of my own creation. I guess I may just have to work it out myself then. $\endgroup$ Mar 10, 2021 at 18:04
  • $\begingroup$ It's also worth noting that the material described as "orichalcum" historically is just a different variety of brass. The properties you've ascribed to your Marbelar, @Korblox, are completely unlike brass - or a gold-copper alloy. It wouldn't make good armour or weapons. Your alloy is imaginary. $\endgroup$
    – jdunlop
    Mar 10, 2021 at 22:22
  • $\begingroup$ @jdunlop I've changed the question a bit. $\endgroup$ Mar 10, 2021 at 22:25

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