8
$\begingroup$

In the story I'm creating, a major weapon type of humanity will be Antimatter based weaponry. This is a fairly new technology, as antimatter production facilities have just reached the size and capacity to realistically produce the stuff in necessary quantities to use. I know that energy-density wise, antimatter is significantly better than anything humanity has produced up to this point, and as such would be more significantly powerful than thermonuclear weaponry. In the modern day, though it has been studied for use in weaponry by the US Air Force, antimatter is not used due to extreme production costs and low production amounts. Aside from production costs, what are the major downsides to using antimatter?

$\endgroup$
  • 3
    $\begingroup$ How are you containing the antimatter? $\endgroup$ – Alexander May 29 at 21:56
  • $\begingroup$ Are you proposing antimatter weapons smaller than planet destroyers? A nuclear bomb is about how small the tiniest antimatter weapon would be (at a guess) and the utility of weapons like that is limited unless you're taking on some really exotic combat scenarios (super-dreadnaughts, etc). I'd need to understand more about what your vision of weaponry looked like. $\endgroup$ – DWKraus May 29 at 21:59
  • $\begingroup$ An antimatter weapon could be as small as you want. It to be, It all depends on how much antimatter you use. A few atoms, a few thousand, few million or whatever. $\endgroup$ – Slarty May 29 at 22:27
  • $\begingroup$ Antimatter is so over-rated in Sci-fi. it is created all the time here on earth. In thunderstorms. And earth is still here, hasn't been blown to nothingness. science.nasa.gov/science-news/science-at-nasa/2011/… $\endgroup$ – Justin Thyme the Second May 30 at 1:21
  • $\begingroup$ the fact one stray shot hitting one of your weapons can wipe out a large portion of your army. $\endgroup$ – John May 30 at 14:02
13
$\begingroup$

It is so hard to keep the matter out and the antimatter in.

Antimatter makes wet dynamite look like Wonder bread. Stale Wonder bread. If you look at antimatter wrong it will blow up.

  1. To contain antimatter you must meticulously keep away any particle of matter. This means the antimatter must be under total vacuum. I am not sure how one would generate a vacuum so completely void of gas molecules. Even one gas molecule in there that touches the antimatter would produce an explosion which would wreck your vacuum apparatus, and there would ensue a (much) bigger explosion.

  2. Vacuums work by pumps that pump out any gas. Antimatter can be any element in theory but so far the antimatter produced has been antihydrogen and antihelium. If your antimatter sublimates off into the vacuum the least little bit, there will be floating molecules of antimatter in your vacuum. When the vacuum pump pumps out an antimatter molecule it will touch the pump innards. This will produce an explosion that will wreck your vacuum apparatus, etc, etc.

  3. Even if you have a perfect God-level vacuum and totally unsublimatable antimatter, cosmic rays are cruising thru everything, all the time. Sometimes they go right on thru the matter here on earth. Occasionally they hit a molecule in the matter they encounter. Cosmic rays are made of matter. If one touches antimatter it will cause an explosion that will wreck your containment apparatus etc.

To contain antimatter you would need some sort of supervacuum - maybe something that electrically charged any nearby molecules and then repelled them by charge. This would work a lot better in deep space where there are fewer gas molecules to begin with. That would work for charged cosmic rays too. You would have to hold the antimatter in place using magnetic levitation or the same sort of charge trick as you use to exclude the gas, directed inward.

All that makes conventional explosives seem so convenient and friendly.

| improve this answer | |
$\endgroup$
  • 1
    $\begingroup$ Most containment systems I've seen in sci-fi are magnetic in nature, but even magnetically containing anti-iron, you still have to make a perfect vacuum and keep anything else out. Which is.... absurdly hard. $\endgroup$ – Andon May 29 at 22:19
  • $\begingroup$ Some fiction has postulated that antimatter can be contained relatively safely inside fullerene molecules. I'm not clear on how this is supposed to work, but basically you have a small atom of antimatter suspended inside a much larger fullerene molecule, which prevents any other normal matter from getting to it; no vacuum or mag-bottle required. (Just don't let the fullerene break down prematurely, or you will have a bad day. But you can store it about as easily as gunpowder.) $\endgroup$ – Matthew May 30 at 1:14
  • 1
    $\begingroup$ I don't think the vacuum has to be as perfect as you're implying. If we use a standard high vacuum chamber feasible with today's technology (assumptions: 0.1 mPa, 300 K, gas is primarily O2, 1 m^3), and every stray gas molecule collides with the captured antimatter, releasing all of its mass energy, the number I get is ~100 MJ - the energy of burning a gallon of gasoline. That's not all that much energy (well, compared to your average mass times c^2). It won't even cause an explosion like lighting a gallon of gas, since it'll be in the form of gamma rays that'll pass through the chamber walls. $\endgroup$ – Gilad M May 30 at 2:15
  • 3
    $\begingroup$ As for sublimating materials, many common materials like Fe have negligible vacuum evaporation rates - we're talking a few atoms per m^3. Cosmic rays are also not an issue, since there really aren't a lot of them, mass-per-second-wise. Even if all the particles that passed through your vacuum chamber annihilated with the antimatter, you wouldn't be able to detect the resulting radiation. I think the issue is you're overestimating the energy of a single atomic-scale antimatter explosion. Like most things at atomic scale, it's still incredibly tiny. $\endgroup$ – Gilad M May 30 at 2:38
  • $\begingroup$ @GiladM - the energy is emitted as a sphere from the reaction. What happens to the molecules of antimatter immediately adjacent to the reaction? I think they may volatilize. But the fact that much of this energy is hard radiation that will exit the vicinity is good to remember. $\endgroup$ – Willk May 30 at 3:23
7
+500
$\begingroup$

When you're dealing with antimatter, there are 3 C's of challenges to overcome: cost, creation, and containment. The OP states that creating large quantities of antimatter is now feasible, and, I assume, cost-effective, so we'll treat the first and second challenges as solved. That leaves containment.

Containing antimatter is very hard, but, I'd argue, not impossible.

Picture a small solid block of antimatter, say anti-iron. Even 1 kg of the stuff would have a comparable yield to the Tsar Bomba, the most powerful nuclear weapon ever detonated$^1$. The best way to keep it contained is to magnetically levitate it (preferably above a high-temperature superconductor) in a perfect vacuum.

Let's first address the issues brought up by Willk in his earlier answer.

  1. Vacuum Quality: No vacuum chamber is perfect, but even with today's technology, we can do well enough.

We can currently build massive vacuum chambers capable of maintaining 130$\mu$Pa of pressure. I'll assume that tiny amount of gas left in the chamber is just air at room temperature (to simplify my calculations, I'll use 300 K and assume pure Nitrogen, with a mass of 28 AMU per particle). The important thing is the order of magnitude. If any energies we get out of this are closer to a campfire than a nuclear bomb, it's probably manageable.

How much energy is the chamber radiating from trace gas molecules colliding with the antimatter? Rearranging the ideal gas law, we get $$ \frac{N}{V} = \frac{P}{k_B T} $$ $$ \implies D = \frac{P}{k_B T} \times M = \frac{(130\times 10^{-6} Pa)}{k_B (300 K)} \times (28 AMU) $$

The total energy per cubic meter of the chamber, assuming all the gas is converted to energy, is the density $D$ times $c^2$: $\sim 131 MJ/m^3$. WolframAlpha says that's about as much energy as burning a gallon of gasoline. Admittedly most vacuum chambers built today wouldn't appreciate being set on fire, but this is the future we're talking about, and they're building this chamber specifically to hold antimatter. This is more campfire than nuke, so it's just an engineering problem.

  1. Vacuum Evaporation: the antimatter (as well as the inner walls of the chamber) will boil slightly in the vacuum, also releasing energy via matter-antimatter annihilation. Is this a problem?

Again, the quantities of mass we're dealing with are too small to matter. Here's a plot of the pressures caused by various metals boiling into a vacuum:

As you can see, iron (Fe) experiences so little vacuum evaporation at 300 K that its pressure is literally off the chart (even after you convert from mmHg to $\mu$Pa). As long as you don't build the chamber walls out of something with a higher pressure like magnesium (Mg), you probably don't have to worry about this.

  1. Cosmic Rays: Random protons flying through the universe will sometimes hit the antimatter core. Is this a problem?

No. Again, it's a matter of scale. According to Wikipedia, the total flux is only about $10^4$ particles per second per square meter (assuming particles with less than 1 GeV of energy won't even make it through the atmosphere). That's far lower than the ambient pressure of the vacuum chamber, so it's negligible.

So what do we have to worry about?

  1. Losing Power: If you want to use these bombs like nukes, you need to be prepared to store them for years at a time, primed and ready. Keeping a vacuum going continuously requires continuous energy, unlike nukes which can just sort of sit there. And you need to build extensive safeguards so that if the power goes out, you don't blow your own country up.
  2. Radiation: As I said before, due to reactions with residual gas in the chamber, your antimatter bomb will be emitting as much energy as a campfire, more or less. This won't necessarily harm the device, but unfortunately it will very much harm anyone not behind a lead shield, as it's in the form of high-energy electrons, positrons, and gamma rays that will very easily pass through the chamber walls.
  3. Transport: This thing makes me nervous just thinking about it. You need very clever engineering to keep this thing from blowing up if you jiggle it in the wrong way. If this is loaded onto a plane or a missile, you need to factor in changes in acceleration and program your magnets to compensate, or it'll bump into something mid-flight for sure.
  4. Flashlights: I'm not kidding. Shining ordinary light on the antimatter will cause it to expel positrons due to the photoelectric effect. I calculated at some point long ago that even if the antimatter were otherwise perfectly contained but you shined a flashlight at it, the resulting gamma radiation could kill you in seconds. Your vacuum chamber probably isn't made of glass or anything, so it's probably not an issue. I just find it funny that antimatter is so volatile that you can literally die by looking at it the wrong way.

None of these things are disqualifying; an antimatter weapon is feasible with enough effort, funding, and ingenuity.

But honestly, is any of it worth it? I'd argue that that's the main reason why antimatter weapons aren't practical: we don't need stronger weapons. No two nuclear powers have ever gone to war, because nuclear bombs are terrifying enough.


$^1$: I'm assuming that all the mass will eventually be converted to energy via good ol' $E = m c^2$. This isn't a safe assumption for nukes, since most of the fissile material gets launched by the explosion before it can release its mass energy. But, on Earth at least, antimatter doesn't have this problem. Once the antimatter gets out, it's going to keep interacting with the surrounding matter until it's all gone.

As user110866 points out, though, where exactly that energy will go is very complicated since there's no sustained chain reaction, so I can't say for sure how much of that will be converted to heat or a shock wave vs just heavily irradiating the surrounding area.

| improve this answer | |
$\endgroup$
  • $\begingroup$ This is good; thank you. I can't put a bounty yet but soon. Would you show how you calculated the mass of the gas remaining in the vacuum? $\endgroup$ – Willk May 30 at 22:12
  • $\begingroup$ The M in that last equation is just mass per particle. N/V is the particle density, so multiplying by M on both sides gives the mass density. Then multiplying by c^2 gives energy density. If you mean how I got 28 amu per particle, that's just the mass of an N_2 molecule. $\endgroup$ – Gilad M May 30 at 22:17
  • $\begingroup$ @GiladM While the average energy density given is correct, it belays the interactions taking place in that scenario. A single N-Nbar annihilation will produce insanely energetic particles which will certainly (multi-resonance) pair-produce. For example see [ arxiv.org/pdf/hep-ex/9708025.pdf ] for the host of particles that a P-Pbar interaction can produce only constrained by scattering cross-section. The threshold for the chiral symmetry breaking is on this level [ arxiv.org/abs/0811.1338 ]: ~ rho-meson mass-energy scale... $\endgroup$ – user110866 May 31 at 1:42
  • $\begingroup$ @GiladM ...hence a cascade effect would certainly be expected within any form of condensed matter. To wit, I think you'd need a complete vacuum. $\endgroup$ – user110866 May 31 at 1:43
  • $\begingroup$ @GiladM I realize I'm not being clear with my math so I'll elaborate: 1 N-28 will interact with a FE-56, in the annihilation interaction alone: 2 sets of 28 annihilation pairs will produce particles with total energies of each interaction on the range of 938 MeV, in addition the e-p pairs will also annihilate at 2 sets of 0.511 MeV. This does not include the additional, albeit much smaller, energy released form the break in crystalline structure. Each interaction will produce 2-4 particles with appropriate fractional energies which will interact with surrounding atoms, hence a chain reaction. $\endgroup$ – user110866 May 31 at 2:00
1
$\begingroup$

Storage:

Antimatter cannot be stored easily or safely. How do you contain it?

The risk to other matter such as equipment and personnel seems quite large. Larger than, say, using a thermonuclear device.

| improve this answer | |
$\endgroup$
  • $\begingroup$ Oh yes. Making plutonium explode is hard. Making antimatter not explode is significantly harder $\endgroup$ – b.Lorenz May 29 at 22:08
1
$\begingroup$

Radiation hazards.

When a particle more complex than an electron annihilates with its antiparticle, the result is a mess of weird gluons whose ultimate child particles depends on what else they run into. Unless you're very careful to annihilate isolated particles, the way people do in physics experiments, you can end up with products like high-energy neutrons and gamma rays flying around. These are exactly the types of byproducts that irradiate the surroundings of a fission reaction and create radioactive fallout.

If you'd like to kill somebody without rendering the entire neighborhood a radiological hazard area, you should stick to lower-energy physics like conventional ballistics or explosives. Maybe a nice railgun.

| improve this answer | |
$\endgroup$
1
$\begingroup$

Things to be used as a weapon require that you have a dedicated "arming" mechanism. It's good if the arming mechanism is redundant to the normal node of activation. It's also good if the mechanism is passive. For production of weapons its good if you have passive precursors and store only a small quantity of the unstable stuff.

By definition in an armed conflict, the opponent will almost certainly try to damage your infrastructure (logistic, technical, administrative). Current methods of storing antimatter safely require continued power.

So in the current view these weapons would be something like nuclear weapons, just worse (at least nukes don't explode when storing them). You would not want to hand out "antimatter grenades" to you foot troops in the scale of 10000s. You would not want "antimatter bullets" in the millions - it would be a logistic nightmare during an armed conflict keeping these safe - landmines, non detonated bombs are already bad enough without having an implicit timer and gamma-radiation poisoning.

So now let's look at the "classical" usecases

  • "super nukes" - as long you are not planning on blowing up planets, fusion bombs seem to work well for most applications
  • "mini nukes" - no state level actor would proliferate such a techology. Use for states is unclear
  • Explosive ammo - i could imagine that these make sense in very limited setting these make sense, but its a borderline case.

The only usecase (beside planet destruction) which i could assume is realistic is "controllable radiation mines". You design the containment in a leaky way that you get a significant amount of gamma radiation and you control the containment in a way that it is linear instead of exponential decay. So you set the load and the timer, and after a few hours it\s safe (if nothing was strongly activated to enter the area), but before that there is a deadly gamma radiation (before that the enemy has the option of destroying the containment - explosion + strong radiation pulse) or shielding it. make many small ones of these and combine it with stealth you can switch on and off the irradiation of the enemy controlled areas at bad times for them.

| improve this answer | |
$\endgroup$
1
$\begingroup$

As others have pointed out, Antimatter is difficult to both produce and contain.

The most well known property of antimatter is that, for each matter particle, there exists an oppositely charged but otherwise identical "anti" particle. The complete picture is a little more complicated as other quantum properties are also reversed. For instance, anti-neutrons are electrically neutral, just like neutrons, but they have opposite Isospin and thus strongly interact like a proton. Thus it is impossible to trap antimatter in the form of a proton-antineutron, or pesudo-deuteron, nucleus.

The most difficult part of production is that antimatter is only created via very high energy photon-matter scattering. The exception to this is positron emission which is very rare. Thus the production of antimatter would require very large machines (particle accelerators) which would consume much more energy then they would produce.

The only anti-particles which can be captured are the charged ones since these can be contained within magnetic fields. Unfortunately grouping large amounts of charged particles creates an electrostatic imbalance, since magnetic fields need to be much stronger than the electric fields they contain, a small amount of charged antimatter requires disproportionately large, yet very precise, magnetic containment which is also very energetically unfavorable.

Aside from production costs, what are the major downsides to using antimatter?

Assuming you were able to over-come these obvious issues, there are some more subtitle ones which would need to be taken into account to use antimatter. @Cadence mentioned the important issue of the products of pair annihilation. To elaborate, pair-annihilation produces very high energy photons, which have the tendency to scatter and are liable to form pair production if anti-nucleons were annihilated. Thus it is very difficult to get a controlled amount of energy out of the interaction and thus it really would be difficult to use it for propulsion.

Using it as a weapon would pose similar problems. It is not a simple matter of computing the rest mass of the antimatter (times 2) to calculate the total energy transferred upon detonation since the high energy radiation will scatter.

The type of antimatter will be important, for example if only low KE positrons-electrons are used, the resultant energy will be too low energy to pair-produce upon scattering and the photons will propagate out in all directions. The reason that nuclear weapons are so incredibly destructive is because of their creation of sustained nuclear reactions; producing chains of highly exothermic reactions and thus enormous explosions. Antimatter annihilation would need to be calibrated to the right energy scale to produce similar chain reactions. Photon penetration tends to be very deep below pair-production thresholds, but this will decrease the tendency to produce sustaining reactions.

| improve this answer | |
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.