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This question already has an answer here:

The setting takes place in an Island 3 O'Neill cylinder. All type of bows included. I wonder if there are things to take into consideration when describing how a person would target and shoot, as well how the arrow flies, compared to bow shooting on earth.

Also, what if a skilled person with a compound bow would shoot straight up; could it technically hit the other side (the side above)? Or would the difference of gravity in the centre of the cylinder prevent such.

Edit: Please excuse the duplicate, these questions did not show up on my search. I understand now that the direction in which one would shoot will be essential; spinwards or antispinwards, and the range for additional drop or reductional drop is equal in length (either x meters "more" or "less" than on earth). One can drop something to determine the direction one stands in.

I would appreciate an answer to, what if one would shoot "to the side" (= not spin- or antispinwards)? Is my guess correct that the drop rate is +/- 0 and one would hit the intended target?

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marked as duplicate by Tim B science-based Oct 1 at 15:40

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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    $\begingroup$ I asked this question not too long ago worldbuilding.stackexchange.com/q/150259/30492 $\endgroup$ – L.Dutch - Reinstate Monica Oct 1 at 15:10
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    $\begingroup$ Good question, I've closed it as a duplicate since I think it's already answered there but anything that isn't covered feel free to ask as a follow on question. $\endgroup$ – Tim B Oct 1 at 15:40
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    $\begingroup$ Also related: worldbuilding.stackexchange.com/q/156146/62341 $\endgroup$ – Starfish Prime Oct 1 at 15:44
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    $\begingroup$ (now I'm strongly feeling the need to work out whether it is possible to shoot yourself with a bow in a rotating habitat, and what the parameters of such a habitat would have to be...) $\endgroup$ – Starfish Prime Oct 1 at 15:47
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    $\begingroup$ it is absolutely possible, you just shoot up at the rotational velocity / pi $\endgroup$ – Nosajimiki Oct 1 at 16:06