World Rules:

  • Travelers are able to move at the speed of light without disruption of their lives. Time passes "normally" for them. They think, breathe, love, cry, and steer the ship as if they were merely crossing the Atlantic.

  • Whatever allows the ship to travel at the speed of light, it does not distort the traveler's view of the rest of the universe. There is no "warp bubble" or "bending of spacetime" to get in the way of what they see. (Edit: I think this is what's getting in some people's way. I don't mean that physics is suspended. I mean that any effects caused by the ship's method of getting to V=c should not be considered as part of your answer.)


After a probably notable amount of time, the intragalactic cruise liner Prinzessin Victoria Luise II has, for the first time, achieved what was previously believed to be impossible: the ship is traveling at 100% c, or exactly at the speed of light.

Little Victoria Luise, who understandably believes the ship is named after her, breathlessly looks out the viewing port. She's excited to be among the first to look at the universe from the perspective of a photon of light. With wide eyes and an imagination filled with the hope of angels and the fear of dragons, she sees...


Question: What, really, would Victoria Luise see outside that view port?

  • Victoria Luise is looking out a starboard view port.

  • The trip is at least 20 light years long and there are stars near (relatively) and far out the view port.

Edit: Several commenters are getting bogged down in the backstory. An observer traveling at the speed of light looking perpendicular to the transit vector would see what? If you believe how the observer got to the speed of light affects that question, then you need to explain why.

It is certainly true that Victoria experienced no time while traveling at the speed of light (from the perspective of a photon, it arrives at its destination instantaneously regardless of distance traveled). However, while traveling across the distance photons impacted physically on Victoria's eyes. So, what did she see?

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    $\begingroup$ The simplest answer is: whatever you want. The physics as we know make it impossible for such a ship to exist and if you've thrown away our current understanding of physics then your imagination is the limit. $\endgroup$
    – chx
    Commented May 25, 2019 at 6:07
  • 1
    $\begingroup$ Liam, I'm pretty sure I got that picture upside down. If you think I got it right, let's talk it through so the edit can be more comprehensive. $\endgroup$
    – JBH
    Commented May 25, 2019 at 7:00
  • 1
    $\begingroup$ @LiamMorris yeah, they are. I didn't realize my mistake until I was done. Frankly, I'm cool to leave the explanation. I apologize for not even looking at the graphic. It's late.... $\endgroup$
    – JBH
    Commented May 25, 2019 at 7:16
  • 1
    $\begingroup$ @LiamMorris unfortunately it would only work until the 3rd image, which has the light refocused correctly to the left. After that all the images would be off one way or the other anyway. Nah. Let's leave it. Thanks! $\endgroup$
    – JBH
    Commented May 25, 2019 at 7:25
  • 3
    $\begingroup$ As the question is opened again, could you please move your answer to an actual answer? $\endgroup$ Commented May 25, 2019 at 21:54

13 Answers 13


I have painstakingly assembled a highly realistic 3d rendering using advanced relativistic raytracing and plausible geometry and position for nearby stars.

Here's a render of the view to starboard:

A glorious vista

I'm sure you can appreciate the thousands of hours of computing time that went into this.

Less facetious answer:

Leaving aside the issues of whether there's any time for your observers to experience stuff in, lets look at the boring relativistic things.

Here's a thing that Einstein cobbled together using some of Lorenz's work, describing relativistic aberration.

$$\cos \theta_o=\frac{\cos \theta_s-\frac{v}{c}}{1-\frac{v}{c} \cos \theta_s} \,$$

This is the effect by which things in space (that are effectively stationary background objects, relatively-speaking) around you appear to be warped to bring light sources together into a region in front of you, centred on your direction of travel. $\theta_s$ is the angle between your direction of travel and the direction of travel of the photon shooting at you. $\theta_o$ is the observed angle of the incoming photon's trajectory The exact reason for this is kinda hard to articulate in simple terms (but related to the fact that light always seens to be travelling at lightspeed for an observer, regardless of what sublight-speed they may be travelling at), but you can reasonably take it on trust that those two gentlemen knew what they were talking about.

This means that as your velocity approaches the speed of light, your entire view gets concentrated into one tiny spot in front of you. You can see that the equation simply resolves to 0 when you reach lightspeed. There's nothing to see to the side. That image above? Totally plausible for an ultrarelativistic traveller.

Here's another thing: relativistic length contraction.

$$L =L_{0}\sqrt{1-v^{2}/c^{2}}$$

Here, $L$ is the length of the ship as observed by some "stationary" observer, and $L_0$ is the actual length of the ship. You'll note that from the point of view of this observer, an object passing at lightspeed has no length. If I shoot a laser at a passing C-ship, how can I hit a side window, when it has no side? I can still hit the front, but that's about it.

I'm fairly certain that this is another way of stating the same sort of thing described as relativistic aberration above. Someone who actually knows relativity, rather than just trying to bluff confidently, feel free to correct me...

  • $\begingroup$ Comments are not for extended discussion; this conversation has been moved to chat. $\endgroup$
    – L.Dutch
    Commented May 24, 2019 at 20:03
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    $\begingroup$ @L.Dutch it was already moved to chat, and now you've linked to another chat room that doesn't contain the most recent discussion. $\endgroup$ Commented May 24, 2019 at 20:10
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    $\begingroup$ See here: chat.stackexchange.com/rooms/94076/… $\endgroup$ Commented May 24, 2019 at 20:10
  • $\begingroup$ to think of it another way, imagine a bullet train in a rain storm that is traveling many times faster than the rain is falling, then the only rain hitting the train is hitting the front as the train plows into it and anything else just can't fall fast enough to reach the train before it passes. so little light hitting the sides it might as well be none. $\endgroup$
    – John
    Commented Jun 24, 2022 at 0:42

On a ship traveling at exactly c, Victoria wouldn't have any time to see any stars -- for her, the ship would arrive at its destination instantaneously due to time dilation.

Sorry for the slightly lame answer...

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    $\begingroup$ @StarfishPrime accordint to the question Time passes "normally" for them. with normally left undefined. Time dilation is perfectly normal to me. $\endgroup$
    – Mołot
    Commented May 23, 2019 at 20:54
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    $\begingroup$ Hoyle's ghost does a much better job explaining; should I delete this answer? $\endgroup$
    – Cloudy7
    Commented May 23, 2019 at 21:09
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    $\begingroup$ @StarfishPrime: Time always passes normally for the observer; that's why it is called proper time. The observer never experiences time dilation. What happens is that as the vehicle approaches the speed of light, time outside the vehicle appears to pass faster and faster, to the point where, when the vehicle travels at the speed of light, time outside the vehicle passes infinitely faster than time inside the vehicle. From the point of view of the travellers the entire distance is traversed instantaneously although when they arrive the universe may be billions of years older. $\endgroup$
    – AlexP
    Commented May 23, 2019 at 23:26
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    $\begingroup$ .. and then there is a problem of speeding up / slowing down. You can't just hit thrusters and go 0 -> c (unless it's fine with you that everything within the ship is melted down due to an infinite G-Force). Then again, it takes infinite energy to accelerate to c from whatever speed it is "before c", so.. such unpleasant outcome is inevitable. $\endgroup$
    – Alma Do
    Commented May 24, 2019 at 15:26
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    $\begingroup$ @AlexP ... which breaks the symmetry of the problem because physics in relativity doesn't work the same in accelerated frames, much like how Newton's laws only apply to inertial frames. Specifically, in an accelerated frame, the spacetime metric changes so that it is no longer minkowskian. So it's not the velocity that causes people on the ship to age less, it's the acceleration. $\endgroup$ Commented May 25, 2019 at 5:10

Let's throw the whole relativistic discussion out the window and just work on the assumption that the ship is doing "something" in such a way that after one second, it is one light second along it's path.

The view outside is incredibly boring. Let's assume I am standing there looking out the window, the view takes up 60 degrees of my vision so that means a star which crosses my view starts 60 degrees from my left and ends 60 degrees from my right. Here's a diagram:

enter image description here

Let's assume my path is the bottom line, does this look familiar?

It's an Equilateral triangle. So if the star starts and ends one light year away, then my path is one light year, which means, at light speed, it took one year for the star to cross my window.

Space is really empty so most stars are even farther away than that.

You can walk up to your window, draw little dots on it where the stars are, go about your day, come back and nothing would have moved.

Looking out the window is boring in terms of natural objects, but maybe there's traffic outside, other ships to watch, but that's up for you to write.

  • $\begingroup$ This would be a mostly-correct answer for a Newtonian universe. There'd be a bit of a brightness shift towards the front and a blind spot towards the rear, and probably something of a position shift, but other than that, things would be pretty boring. $\endgroup$
    – Mark
    Commented May 24, 2019 at 2:44
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    $\begingroup$ Based on the rules the question has, I think this is the most correct answer. Without warping or worrying about the impossibility of light speed travel because of relativity you're left with basically all the same equations as a much slower ship. $\endgroup$
    – JPhi1618
    Commented May 24, 2019 at 14:42
  • $\begingroup$ @Mark Would rooms inside the ship be the same way? Dark on the aft side? $\endgroup$
    – Muuski
    Commented May 24, 2019 at 15:04
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    $\begingroup$ @JPhi1618 this might be correct based purely on the question as written, but JBH clarified in comments that relativity is not ignored. $\endgroup$
    – Rob Watts
    Commented May 24, 2019 at 15:55
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    $\begingroup$ @Rob Watts I read that long thread about relativity. My answer was to point out that if people could stop bickering about details, the answer is boring either way. Either we have a boring unmoving landscape like I have described or the trip is over instantly like others have described. Unfortunately the universe is incredibly boring when viewed from the naked eye. $\endgroup$
    – Muuski
    Commented May 24, 2019 at 16:00

There is a game (made by/with physicists from MIT some years ago) that models the player approaching the speed of light. This leads to multiple effects on vision:

  • Doppler effect:
    red- and blue-shifting of visible light, and the shifting of infrared and ultraviolet light into the visible spectrum
  • Searchlight effect:
    increased brightness in the direction of travel
  • Time dilation:
    differences in the perceived passage of time from the player and the outside world
  • Lorentz transformation:
    warping of space at near-light speeds
  • Runtime effect:
    the ability to see objects as they were in the past, due to the travel time of light

I don't understand the physics behind this well enough to do more than copy pasting what the game description lists, but as far as I remember the game includes further explanations (and you can of course use the names of these effects to look for more details).

  • $\begingroup$ The game models relativistic effect. Since the universe allows exact $c$-speed of massive object, this is where the model breaks down and the game ceases to be useful. (The main question is, how did the ship obtain $c$ speed?) $\endgroup$ Commented May 24, 2019 at 15:00
  • $\begingroup$ @RadovanGarabík, that isn't the main question, that's the backstory that doesn't matter for the purpose of my question. If you only want questions that are 100% attributable to real-world conditions as we currently understand them, hop over to Physics or Astronomy. $\endgroup$
    – JBH
    Commented May 24, 2019 at 18:41
  • $\begingroup$ Nicolai, I sincerely appreciate this post. It's hugely valuable to both me and others. I've added the game link to our list of worldbuilding resources. $\endgroup$
    – JBH
    Commented May 24, 2019 at 18:45

Yalls' universe is so boring!!

Naturally, what little Victoria Luise actually sees from the view port (one could have hoped she'd discover this wonder from the starboard side smoking lounge, but one supposes that's for adults only, and not small girls!) is far more interesting than mere science can describe! A wonder indeed for the eyes and a feast for the imagination. And how lucky she is to experience it first hand!

First, it's important to understand that bits of Light travel along their appointed paths, wavewise, very quickly. Like the velocipedes Miss Victoria Luise is used to seeing speeding along in her home city. Because she is a well to do little girl, her accustomed mode of transport is a sedan chair carried along by two amiable fellows of the household staff. So, she's used to seeing the electro-telegram boys with their curious flashing devices strapped to their backs whizzing by at such a rate that she can scarcely make out their House liveries, to say nothing of the contents of the e-tels they're carrying. And like the velocipede riding boys of home, she knows from her physioastrological studies that Light moves even faster than the fastest velocipede, faster than the great tram-ships that ply the oceans and faster than the fastest of electro-trains that can bring one from the kaiser's busy parliamentary capital of The Hague all the way to the Oriental Empire's capital at Peking overnight!

Second, it's important to understand that these bits of Light are travelling in all directions all the time. It's just like the traffic whizzing through, around, over and under St. Wyziwygus's Circus downtown. At first glance, all seems a bizarre chaos of velocipedes, electro-trams and pedestrians. They're all moving in every conceivable direction and all just as fast as they can. Apart from the poor walkers, who appear to be slothily trudging along among a whizzing cloud of faster traffic.

But now little Miss Victoria Luise has gotten herself upon the proverbial velocipede and she can now see Light for what it truly is!

The View Aft

Looking aft, as the Prinzessin accelerated towards her magic velocity, she'll see what appears to be a fuzzy wave approach the grand Ship. Due to the amazing properties of the view port itself, she can just make out the lines of Light, breaking like dolphins on the ocean, at the Edge of the luminal breakwater. What she can not see from her vantage, and this is a shame, is that the Edge surrounds Prinzessin entirely and demarcates that place where the mighty engines have brought the ship up abreast of the Light cast off from the Sun some hours ago while the crew were easing her up to cruising velocity. The Edge looks fuzzy because it is not possible to maintain perfect velocity. For some fractions of a moment, Prinzessin might be travelling just shy of or just more than 1 luminal; thus there will be moments when she eases ahead of the light from Sun and some moments where that light catches her up and passes by, which causes a bit of haze to surround the vessel back towards the engineering department. Adding to the haze of the Edge, of course, is orthogonally travelling Light, that is moving perpendicular to their course. As Prinzessin whizzes by those pathways, the Light appears to sort of bunch up, mixing and separating in wonderful bands of colours and hues that compress at the interface of the Edge. A spacebow that travels with the Ship and would appear much like a glory or rainbow surrounding an airship.

Perhaps just at the edge of her perspective, she might get a glimpse of the Void! This is a spectacular phenomenon that can really only be appreciated when the Ship travels just slightly faster than 1 luminal for a short time. If the engineers can provide such a mighty burst of speed, Victoria Luise will notice that she is suddenly failing to see the Edge. As Prinzessin overtakes the Sun's ever older Light, that Light which they were just flying abreast of has now disappeared behind the vessel's wake and, being slower than the Ship, is now invisible. As the Prinzessin slows again, the Light will rapidly overtake and that part of the universe will again become visible. But the change will not be so fast that it is not noticeable! Victoria Luise will actually be able to see the Front as it careens forward like a cavalry charge overtaking its lead horse. The sizzle of photons as they overtake the Ship will form a brilliant and electrically exciting spectacle!

The View to Starboard

Luckily for little Miss Victoria Luise, her viewing port allows her to see quite a bit of interesting external infrastructure of the great Ship. From this vantage, she can tell when Prinzessin is charging forth towards 1 luminal. For there is a bright beacon light some distance below her port which illuminates some of the vanes of the great Scoops that draw in interstitial matter for the powerful engines. As the Ship moves faster, she can see the leading edge of the beacon's light. As with the Front of Light coming in from the Sun, so it is with the lesser lights of the beacons: as the Ship catches up to them, she can see the effects of the photons dancing at the edge, beyond which there is no light. As Prinzessin gains speed, the Front wavers and churns, its bright hues alive with squillions of photons bunching up in the wave; until at last, the Ship passes into superluminality and Front dissipates, and all the Light is sucked from beacons and disappears into the Void!

The View Fore

Peering towards the front of Prinzessin as she plies the interstitial main, little Miss Victoria Luise will be in the view of her life! For there she may see all the stars familiar from her astrology lessons, but their colours shift and waver, now bluing and now redding in an exciting arc of lights emanating from the bow of the great Ship! Here is a the light fantastic, the mad tarantella of ancient photons dashing in from the depths of space beyond her comfortable world, and like two madly careening velocipede boys passing in the streets of the city, Victoria Luise can catch no more than a searing blur as those bits of Light careen screaming through the Bow Arc and pass like a burst of sudden lightning out of sight into the Void beyond Prinzessin.

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    $\begingroup$ God bless you, Elemtilas. $\endgroup$
    – JBH
    Commented May 24, 2019 at 18:34
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    $\begingroup$ This reminded me of Traversing the Luminiferous Aether. $\endgroup$
    – Ray
    Commented May 26, 2019 at 16:30
  • $\begingroup$ must...remember...Kingston's...smoking...trunks...next...time...! $\endgroup$
    – elemtilas
    Commented May 26, 2019 at 22:08

She will see a flash of white, and then she will be permanently blinded.


It is certainly true that Victoria experienced no time while traveling at the speed of light.

For practical purposes, the trip is instantaneous. That means all photons that impact on the kid's retinas do so at the same time.

The longer the distance travelled, the greater the amount of photons caught. For even just a light second, she is going to collect an awful lot of radiation. Even if you filter X-rays, UV... There is still much more in a light second trip than what you would get from a strong laser pointer.

To find out the damage: find out how much light she would be getting in her eyes if she were travelling at regular interstellar speeds (i.e.: the sun's orbital speed around the galaxy, 200km/s). Multiply that luminosity by the distance travelled, since her retinas will cover that much area in zero time.

Next time keep the spawn away from the windows.

  • $\begingroup$ Technically see will "see" nothing, as almost all the incoming light will be blue-shifted out of the visible range. Instead her eyes as well as herself and the whole ship will be immediately reduced to a plasma by the resulting gamma radiation... $\endgroup$
    – mlk
    Commented May 24, 2019 at 10:09
  • $\begingroup$ @mlk realistically yeah but the OP handwaved that away. $\endgroup$ Commented May 24, 2019 at 12:23
  • $\begingroup$ Clearly the windows would be tested with full spectrum cameras, and shielded accordingly to protect the passengers or the lawyers would have a field day. $\endgroup$
    – cybernard
    Commented May 24, 2019 at 14:08
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    $\begingroup$ I didn't handwave away the doppler shift. But that doesn't negate Renan's answer, either. Photons traveling 90° to the vector of travel wouldn't be shifted, making Renan's "she's blinded" observation very, very valid. $\endgroup$
    – JBH
    Commented May 24, 2019 at 18:36
  • 1
    $\begingroup$ @JBH I was thinking more of handwaving that the amount of radiation would not kill anyone, since you allow for observation of the outside. $\endgroup$ Commented May 25, 2019 at 13:19

Horizontal Stripes.

Your question explicitly states that in your universe no spacetime distortion or whatever happens, so the answers based on theoretical physics are altogether wrong. They are, with some exceptions such as frequency shift (which is very much provable, and observable), mostly unprovable speculations in our universe, too -- but they're by definition wrong in the universe you depict.

So what you would see is the same kind of horizontal stripes that you see in a high-speed train, only much darker. Very distant things being somewhat less blurry than closer things (though due to your ship moving very fast, things would have to be very far away).

Because, well, your eyes still have the same basic properties as they have in our universe (unless you say they don't).

While the eye tries hard to re-fixate ("saccade") when stuff is moving, there is a limit to what those poor little muscles can do (plus, your neurons are not infinitely fast). Which is approximately an angular speed of 720° per second, maximum. If the exterior moves too fast (or rather, is stationary and you move), the eye becomes unable to re-fixate. That's the blurry view outside a high-speed train.

By itself, our eyes are extremely susceptible to motion blur. Every photoreceptor is, more or less, even the fastest camera chip. Biological eyes, however, which involve a complicated G-protein coupled signal pathway going off, are prone to motion blur or "afterlighting" in particular.

Why would your view be much darker? Well, you move so fast that the larger amount of light moves backwards, the "sideways" component of any light ray, or photon, being smaller than usual. Thus, everything will be "darker". Since light coming from the front will travel at twice the speed of light, and light coming from the back will be "standing still", your blurred stripes would be lighter (flashing white) towards the front, and darker towards the rear.

  • $\begingroup$ What my question actually says is nothing about how the ship travels (e.g., the nature of its engines, etc.) get in the way of the observer. I see where you jumped to the conclusion, though, and apologize. nevertheless, I'm delighted that you brought out one aspect of what's going on: the horizontal lines that would appear on Victoria's retinas due to the T=0 nature of the travel. $\endgroup$
    – JBH
    Commented May 24, 2019 at 18:55

Frame challenge:

We don't know, and may never know

As per our current understanding of physics, objects with mass can not be accelerated to the speed of light. As such, there are no images to confirm or deny any of our speculations, and there may never be. It may be physically impossible to take a photograph at the speed of light as we may never find a way to accelerate objects with mass to 100% the speed of light. This means we would never have a point of reference to compare Victoria Luise's experience to.

Little Victoria Luise would experience something indescribable, it would be like trying to explain colour to someone who was blind, or love to someone who could not feel, or life to someone who could not experience death. She would see something beyond what words could explain as currently we are blind, we can not see through her eyes to experience what she has experienced – mere words would not be enough to explain it, you would need to see it, to feel it, to be in the presence of it, to have any idea of what she has seen.

And I think that is something truly magical, how this little girl would have seen something that she, and only she, would ever know.


Moving at exactly the speed of light means that no time at all passes inside the ship for the entire duration of traveling at the speed of light. All the light that impacts the ship during that duration hence hits the ship in literally no time at all, meaning that the surface is subjected to light impact of literally infinite energy density. Each photon and atom impacting on the front would also have infinite energy. I can't imagine any material able to stand up to that, much less any human eye trying to view it (even if there was any time to view it, which there isn't).

Another issue is that your ship would have literally infinite mass. At the moment it hits the speed of light, all objects in the universe would start moving towards it with infinite acceleration, reaching near-light speed in an instant. The universe would start collapsing on itself. This acceleration would be delayed until the gravity wave reaches the stars and galaxies, but the effect would be instantaneous from that moment, no matter the distance.

Even if you use hand-waving metaphysics to bypass the mass/gravity problem (which might be necessary to reach light speed), you still have the problem of impacting photons and atoms.

One way to get around all this: Convert your entire starship to light, which per definition travels at light speed, have it received by a large dish, which then converts the light back into solid matter. In this case, however, there would be no view, as the passengers would experience no time at all for the journey.

  • $\begingroup$ "the surface is subjected to light impact of literally infinite energy density......I can't imagine any material able to stand up to that", Apparently the OP's insistence that light-speed has been achieved and the subject - Luise - is able to go about her business of being a curious child, suspends disbelief re the front shield from matter of various types. (Maybe the science-fiction tag should have been used), or maybe the only way is "light ship". +1 $\endgroup$ Commented May 24, 2019 at 18:37
  • $\begingroup$ @Hoyle'sghost +1 was a bit premature. Energy density may be mathematically defined by time (division by zero = infinite), but that doesn't mean squat. Energy density isn't what's impacting the front of the ship, just the charge of the photon. It would deliver the same energy to the front of the ship as it would a stationary observer. The serious sunburn caused by experiencing all those photons over a distance would need to be dealt with - but infinite density defined by time != infinite energy. It's a fixed number that could be dealt with in design. $\endgroup$
    – JBH
    Commented May 24, 2019 at 18:52
  • $\begingroup$ @JBH It's implicit in her having time to walk across to the porthole that the ship's built to cope with the bombardment - no matter how you define it. Damn, I meant to go to bed. $\endgroup$ Commented May 24, 2019 at 18:57

A disclaimer. I'm an EE, not an astrophysicist. My own answer is coming from the "... but I stayed at a Holiday Inn last night!" perspective. And I rank my own understanding low enough (hence the reason for asking the question) that Holiday Inn could legitimately be considered an accredited source of doctoral degrees. Fair warning, let's begin.


Many of the answers and comments pointed out that Victoria's actual time spend looking at the stars while at light speed is zero. They're absolutely correct. To be fair, I did not explain events along an axis of time. Everybody's right, Victoria couldn't walk up to the window while the ship was traveling at the speed of light. So, the Captain announces that the ship will hit lightspeed "soon" and everybody should get to a window. Victoria arrives at the window while V<c, experiences V=c, and then V<c. What's left in her eyes includes everything that happened while V=c even if her brain can't process it until V<c.

However, some of the answers/comments seem to think that time action has stopped for Victoria (and the incoming photons) while V=c. Nothing could be further from the truth. She experienced every millimeter of the voyage while traveling at the speed of light. So did all those photons out in space. Relativity doesn't mean everything stops, it means everything happens simultaneously and instantly.

All those photons... striking poor Victoria's eyes at the same moment. @Renan's answer points out the most likely outcome. But there are complications, some brought out in one answer, others in another. Let's walk through it one step at a time. First, some charts showing time, distance, and velocity.

enter image description here

The figure on the left shows us velocity vs. distance. Distance is involved. Victoria's time may not advance, but the distance is being covered. So my question could have been asked (and perhaps should have been asked), "from some point D0 when V=c until some point D1 when V≠c, what did Victoria experience from her brain's visual perspective?" (Even that might have been closed. Relativity can make one's head hurt something awful. So can paintings by Picasso. It's probably all the same problem.)

The figure in the middle shows us Te or the "time experienced by Victoria" vs. distance. Yeah... I didn't mark D0 and D1 on the charts, but they're the points along D where V=c begin and end. From the perspective of a stationary observer, time experienced by Victoria (Te) slows down while approaching and leaving V=c.

The figure on the right shows (*ahem*) what Victoria experienced from our point of view, from Victoria's point of view (people will point out how nasty that description is. Yeah. I get it.). Or Te vs T. Time for Victoria (even though she doesn't perceive it) slows to zero then picks up again. (BTW, this is commonly misinterpreted as time travel. It isn't. Frankly, it's not much different from perfect cyronics. But that's another discussion. Probably one involving Buck Rogers.)

My point is, everything that occurs during the transit between D0 and D1 is experienced by Victoria in one magical (and massive) instantaneous burst.

But what happens?

This is where Doppler, Lorentz, Einstein, a bunch of other folks, and a bunch of people on this site (all smarter than myself) all chip in to create a lovely soup. We're going to add effects one effect at a time. Yup, I'm assuming effects are cumulative. They probably aren't, but remember that spherical horse (why Wiki has it as a spherical cow I'll never know. It was always a horse in my classes.). Let's start with @Hoyle'sGhost's answer and the doppler effect.

let's assume that, looking out the starboard viewport, all you saw was a field of uniform white. That means a lot of photons of all kinds of wavelengths that Victoria's eyes interpret as a smooth, comfortable, field of white. Like this:

enter image description here

You can edit this answer to see that I really did load a 50x50 pixel white square. It's there. Trust me. As the ship accelerates, photons start shifting. Photons shift red to the left, blue to the right, and the faster we go the more they shift. The important thing to remember is that photons approaching the ship perpendicular to the travel vector aren't shifted. You can experience this audibly with a train. When it's right in front of you, it sounds normal. Oh, we're really bookin', so a bunch of these photons are shifted outside what Victoria can see. Maybe something almost certainly not like this:

(An astute observer will realize that I have the honking picture upside down. She's looking out the starboard port, which means it should have been blue to the left, red to the right. Rats. It's late, so I'm not going to change it. You'll get the picture.)

enter image description here

OK. Next we need to deal with @Muuski's and @Damon's answers. One of the most amazing advances in race car video games (occurring back in the 80s, as I recall) was the advent of depth perception: that we perceive objects closer to us to move by more quickly than objects far away. I'm sure there's a fancy word for this effect — I just can't remember it. The reality in our case is that, as @Muuski reminds us, space is really empty and stars are really far away. But we're in a ship traveling at the speed of light across a distance of light years (more faults of my question: no start point and no end point). But even if we were traveling only one or two dozen light years, there are stars that would shift position (perceptually from Victoria's POV, of course) that in the T=0 moment she experiences during V=c travel, a line would be drawn by that star's photons across her retina due to the motion of the ship along D (see figures above). Of course, the more distant stars would remain dots. And all this is doppler shifted (oh, BTW, I'm ignoring relativistic doppler shifting for the sake of my explanation. Another spherical horse.) So, now we get...

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Which is where Star Trek stopped representing the truth, if any of what they did is true in the first place.

Finally, after an amazing conversation with @StarfishPrime that I'm pretty sure impressed me a great deal more than it impressed him it seems that some magic happens next. Magic, I say, because when it comes to future light cones, past light cones, lorentz contraction, and the cool math he mentions in his answer, the light's going to shift boward (or forward, but toward the bow, either way). Since precious Victoria is looking our the starboard viewport, I expect it to shift to her left (fool me once...). It will also contract toward a center point, though I'm not convinced completely as she's not looking out the front of the ship (go read that conversation and realize there's a boatload of data that I couldn't access for better understanding. Remember, Holiday Inn...).

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And that brings us back to @Renan's post. All those photons impacting on the ship over all that distance... (yeah, Starfish, I know you don't think this'll happen. The pancake. I'm just not convinced. Future/past cones and stuff.) all while little Victoria sits there, immobilized in time (so to speak) because everything's happening simultaneously at T=0.

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That picture really doesn't do the moment justice. All those bright white, red, and blue spots? They'd be blinding. Completely blinding, like looking into a camera flash, but much more precise. So much so that when poor Victoria looks away (V<c) to see people around her, it would look something like this:

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The green spots are where the red from the red-shifted light affected her eyes (overstimulating red leaves a green spot in your vision). Likewise, yellow for the blue-shifted light. I'm probably wrong on this one — they'd be black, too, due to the brightness of the flash — but it's possible that you'd get some temporary green and yellow from the weaker (darker) shifts.

Or maybe @Hoyle'sGhost is right and she'd see nothing due to @Renan's answer that the flash would blind her completely. But the above picture is much more fun — and it's what you get when you use spherical horses.

Am I right? HeckifIknow. But the the lawsuit filed by little Victoria Luise's parents against the cruise liner and its captain for not having the brains to close the shutters while the ship was at V=c would make a good story.


If she is looking outside, horizontally, then she would likely see a whole bunch of horizontal lines. If the ship is moving in any sort of arc, then the lines would follow that arc, but that's another problem.

Every body in her field of view (assuming she is flying in space where planets are too far away to see) will emit light in a more-or-less spherical manner. This means there is a functionally solid sphere of photons in a radius of (age of the star * c).

By intersecting through this sphere with your character's eyes, the eyes are looking at an eye-sized slice of this sphere of light. This goes for every star within her vision. She would only be seeing whatever photons are in that particular point in space.

Mileage would vary depending on the thickness of the craft, as it needs time to pass through the ship to her eyes, however any window where her position relative to the bow-side of the window is further than the thickness of the glass would do the trick.

An interesting effect is that, if she is looking towards starboard, stars to her left will have their light shifted towards blue and eventually become invisible, while stars to the right will shift towards red, and eventually become invisible. For an indefinitely small period of time, a star in the direct middle of her field of view would appear it's original color. Additionally, due to the shifting outside of the visible spectrum, this band would be incredibly thin, so it would look like French flag confetti in the middle of the window.


There is no consistent model of reality in which massive particles are moving at light speed and other particles are not, and the two interact.

In order for the person on the ship to see the universe, there must be a way to transform their frame of reference continuously into the frame of reference of the emitting light. And there isn't one.

You have asked the question "what is the height of a square triangle", without the mathematics to understand that you are asking for a figure to have exactly 3 and exactly 4 sides. The "warp bubble" or "bending of space time" is how physics can generate a continuous transformation of reference frames between the light-speed traveling light-seers and not light-speed traveling light emitters.

Physics answers the question of what light you see by tracing what paths the light travels over. With no path, there is no light to see. With no "bending of space time", there is no path.

Now, what you could do is try to throw out our current physics.

You could talk about worm holes, or equivalently you could have the ship move perpendicular to our 3-space into a hyperplane that has a shorter route to the destination. We could be a simulated reality on some hyper computer, which when you type in the console cheat code the laws of physics change along a path permitting light-speed travel. As you travel, the computer displays some physics-unrelated UI in demonstrating where you are. When you give the halt command, the computer builds a brand new reality in which everyone remembers you being at the source location, but you are at the destination location, in such a way that all sentient beings in the simulation have roughly the same experience and continuity of consciousness.


In reality, this would be an impossible question to ask. The light behind you would never catch up, and the light in front of you would be blue-shifted so high that it would be like peering into the generator of an x-ray machine. Either way, you'd see nothing.

So you have to ask why the people can move at the speed of light. Is it because light actually moves faster in your world? Maybe light there truly is instantaneous, in which case you'd see a boring static star field.

It wouldn't be as bad as some of the answers suggest it is, however. You know how the sky looks different in the summer and winter? That amount of difference would happen in sixteen minutes. It would be like watching the minute hand on a clock move. Occasionally you'd see something fly by and think, "damn, that could have killed me," but for the most part it would be boring.

Except maybe for whatever you were using to deflect things in your path. That's what the big dish on the front of the Enterprise is for. While you're moving at the speed of light, anything in your path is shooting at you at the speed of light. Even at a meaningful percentage of C, you'd be intercepting a huge multiple of the normal particles and light in your path.

If light really moved at the same speed, it would look like someone directly in front of you was shooting you with a really powerful laser, and that's just the light. The particles would be like a cosmic particle beam, and you better hope there are no small rocks.

So, yea, you need a deflector shield. I imagine it would look like a rainbow umbrella, but that's just in my head.


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