I've been poking around similar posts, but none seem to contain the information I'm looking for. I'll try to keep it brief.

In the year 20XX, some powerful organizations are trying to "land" an asteroid using a combination of aerobraking, carefully planned orbits around the sun, and a powerful swarm of rocket engines.

Rocket launches have become significantly cheaper in this time period than they were in the early 21st century. The plan is to send a rocket swarm to a relatively small metallic asteroid --possibly no more than 20m-100m across-- and tow it ahead of earth's orbit around the sun. Over the course of X years, the asteroid will be decelerated to the point that the earth will slowly catch up to it in a relatively gentle manner until it begins a controlled re-entry using a combination of natural aerobraking, parachutes, and a final burn by the attached rockets. Hopefully, by the time the rock lands, nobody dies and some billionaires become even wealthier.

Q: Utilizing current or projected near-future technologies and assuming that rocket launches become very cheap and routine, is it plausible to "land" an asteroid in the way described or will the earth's gravity just re-accelerate it to apocalyptic speeds?

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    $\begingroup$ I've adjusted your title to match, what I understand to be, your question - please feel free to change it further if I am mistaken - but try to put at least a similar amount into of information into it, as the previous title was basically useless $\endgroup$
    – dot_Sp0T
    Feb 5, 2019 at 10:36
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    $\begingroup$ It's not hard to land an asteroid on Earth. The hard part is keeping it from burning up on reentry and from wiping out life on Earth by the dust kicked up when it finally stops. $\endgroup$ Feb 5, 2019 at 10:37
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    $\begingroup$ @JohnDvorak True, but the question is specifically landing an asteroid while avoiding those scenarios... $\endgroup$ Feb 5, 2019 at 10:46
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    $\begingroup$ I entirely understand your desire for the hard science, however with it potentially involving future/hypothetical tech, this limits the possible answers you will be able to receive, i would recommend science based might be a better fit, unless you only really want current tech level answers which can give you that hard science data $\endgroup$ Feb 5, 2019 at 11:31
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    $\begingroup$ To be honest my first reaction is that it'd be cheaper and easier to put the manufacturing facilities that would consume the asteroid in orbit, rather than try to bring the asteroid down to the ground. $\endgroup$ Feb 5, 2019 at 20:31

7 Answers 7


The Approach Needs Work

As proposed, your question isn't based on realistic orbital mechanics. Placing an asteroid on Earth's orbital trajectory but "ahead" of it would be inherently unstable for the asteroid unless it was at the L4 Lagrange point. Even if this was a stable configuration, slowing down would change the orbital trajectory (the orbit would become "lower" or closer to the sun, and more elliptical) and Earth wouldn't "catch up" to it because they would be in different orbits. To actually get an asteroid to Earth, you would want to first put it into some Earth-centric orbit. This would be done using the same methods used for spacecraft: taking advantage of favorable conditions for flybys with other bodies to alter trajectories (slowing, changing direction), possibly spreading high-efficiency thrust over long periods (e.g. with ion thrusters), entering the Earth-Moon system on a low-energy transfer orbit, and then using rockets to enter directly into Earth orbit. In fact, NASA was going to do this with a roughly 4m asteroid but ARM was cancelled in the 2018 budget. Obviously as the asteroid size increases, the mission costs increase by at least the cube of that (volume being proportional to the cube of radius), but this would be doable with your cheaply launched rockets.


I see that others have already done an in-depth analysis of the energy requirements in some form or another so I wont get too deep into the actual landing. I will say that if cost is no object there is probably a way to do this using a combination of methods such as aerobraking, heat shielding (coatings and bolt-ons), supersonic drag chutes, and thrusters. If all else failed the asteroid could be separated into smaller pieces, which would guarantee a workable solution if you broke it into enough pieces. This depends on if landing as one chunk of rock is a hard requirement. Here is a similar question, to which someone gave a much more complete response.


If this setting is science-based, I would take a hard look at how much you need the asteroid to be on the surface. Can what you need be done in orbit? What about lunar orbit? Can you take only certain parts/materials of the asteroid to the surface? If you are going to consider the costs at all, I have a feeling that landing an asteroid on Earth is going to be prohibitively expensive.


I don't think it is plausible.

Let's simplify the scenario, assuming the asteroid is a sphere. For 20 m radius we have a volume of

$V=\frac43 \pi r^3 \approx55300 \ m^3$

Considering the density of iron, this corresponds to a mass of $M=5530 \ m^3 \times 7870 $$kg \over m^3$$= 43.5 \cdot 10^6kg$. Its market value would be about 3 million $.

If this body is orbiting Earth, it will be moving at about 7 $km \over s$, while on landing it will be still. It means we need a way to dissipate its kinetic energy, which will be

$K=\frac12 mv^2=1.06 \cdot10^{15}J$

which is $\frac14$ of a Megaton of TNT.

For comparison the Saturn V had a mass of $2.97 \cdot 10^6 kg$ and carried a payload of $140 \cdot 10^3 kg$ to LEO.

You would need $43.5 \cdot 10^6 \over 140 \cdot 10^3$$=310$ Saturns V to slow down the asteroid from orbital velocity to rest without burning it in the atmosphere.

Even assuming that we can double the payload of a Saturn V while keeping its mass constant, we would still need 155 of them to perform the trick.

They would need to be ready to use in LEO, so for each Saturn V assembled in orbit you would need $ 2.97 \cdot 10^6 \over 140 \cdot 10^3 $$=21$ Saturn V, totalizing $155\times 21=3255$ launches, without accounting any safety factor in it.

If you assume you can have 1 launch per day with no interruptions it would take about 9 years just to assemble the whole thing in LEO. And, as AlexP pointed out in their comment, all of this would need to cost less than the price of Earth harvested iron. That would happen, at present prices, if the rockets costed less than $3000000 \over 3251$$\approx 1000 $ $ per launch. Not even a car is so cheap.

Therefore, no, I don't think it is possible.

  • $\begingroup$ Your main issue with this seems to be the number of rockets needed, however the question states that rocket launches are both cheap and routine. I'd recommend stating why being able to launch 300~ rockets into orbit cheaply is not a solution. $\endgroup$
    – Kyyshak
    Feb 5, 2019 at 11:51
  • $\begingroup$ 300 rockets is surprisingly little... even 3300 is. $\endgroup$ Feb 5, 2019 at 12:06
  • $\begingroup$ @JohnDvorak, it's not little if you want all of them to work properly together. 1 single failure and the rock slams down. The N1 had "just" 30 boosters and was never able to have all of them work together. $\endgroup$
    – L.Dutch
    Feb 5, 2019 at 12:17
  • $\begingroup$ I hope that rockets become extremely cheap, because at current prices 43,500 tonnes of iron is about 3 million dollars... $\endgroup$
    – AlexP
    Feb 5, 2019 at 14:20
  • $\begingroup$ @AlexP, thanks for the hint, I embedded it in my answer. $\endgroup$
    – L.Dutch
    Feb 5, 2019 at 14:27

You can probably do this, but it'll be very hard

To do it the way you suggested is probably not the best way. Having the orbit follow the same as earth's is unnecessary, and will cost a lot more energy that would be better used elsewhere.

To make it less hard you should:

  1. Choose an asteroid that already has a close encounter with Earth. A great many of them already pass within 1 lunar distance from the earth. 99942 Apophis might be a candidate, but it's a little too big.
  2. Choose as small an asteroid as possible/economical as it will take much more energy to move a large asteroid.

The steps:

  1. Use a series of gravity tractors to adjust the earth encounter to skim the atmosphere the atmospheric encounter should be constructed so that it puts the asteroid on an orbital path. Note that the gravity tractors will require years to alter the path of the asteroid, they should use a combination of ion drives and solar sails to maximize their efficiency.
  2. The asteroid will have to be coated in heat shielding materials in order for it not to burn up in the atmospheric breaking process. A series of landing missions on the asteroid will be needed for this step.
  3. Once the asteroid is in orbit, additional atmospheric breaking operations will be needed to reduce the velocity of the asteroid and lower the orbit.
  4. For reentry you will need to install a lot of drag chutes etc to avoid catastrophic impact.
  • $\begingroup$ Chutes aren't going to be able to stop an asteroid. $\endgroup$ Feb 6, 2019 at 6:36
  • $\begingroup$ Neither parachutes nor ablation will slow down a large mass like the asteroid. (It's the square-cube law at work: The mass of the asteroid scales as the cube of its diameter, while the stopping power of air pressure scales as the square. That's why big asteroids get to the ground and make big craters, while little ones break up in the air. Also, an iron asteroid is around 5x denser than a spacecraft, which also works against. Parachutes don't work at high speeds. Spacecraft use air resistance on the heat shield to slow down to parachute-safe speeds, but that doesn't happen with an aseroid.)) $\endgroup$
    – Mark Olson
    Feb 7, 2019 at 14:32

There's two big problems with your approach, besides those other answers have mentioned.

First is orbital mechanics. You say that you will start by moving the asteroid to a solar orbit similar to Earth's, then slow it down so Earth catches up. This doesn't work how you think it does. When you slow it down relative to the sun, it will fall to a lower orbit. You can keep the highest point in the asteroid's orbit on Earth's orbit, but the rest of the orbit will fall below Earth's. This makes it more difficult to time it right so that the Earth and asteroid end up in the same place at the same time. Worse yet, if you do manage it, the asteroid and the Earth will be traveling around the sun at much different speeds even before the Earth's gravity really kicks in. The closest approach will be, at minimum, 11km/s. This is because, relative to the Earth, the asteroid is on a hyperbolic trajectory. All hyperbolic trajectories are at or above escape velocity (~11km/s for Earth) at their lowest point. So take L.Dutch's number of needed Saturn 5's and multiply it by 1.5 or so.

Second, you have to deal with the structural integrity of the asteroid. Many asteroids are not single solid rocks; they're big clumps of gravel barely held together by their own gravity. The hundreds of Saturn 5's L.Dutch suggests will shake it apart. And even if you use gentler engines, Earth's gravity will pull it apart with tidal forces. So even ignoring the economics and logistics of actually getting powerful enough rockets to do this, for many asteroids it won't even be possible.

  • $\begingroup$ I don't think the kinetic energy factored into L.Dutch's answer other than as a demonstration of magnitude. Also, I believe he was suggesting 7km/s as it is the lowest/slowest you could really go in Earth orbit before the altitude forced atmospheric decceleration and entry. So e.g. a capture/circularization burn to go into LEO before descending to the surface. $\endgroup$
    – ben
    Feb 5, 2019 at 21:24
  • $\begingroup$ You still have to get rid of 4km/s. $\endgroup$
    – Ryan_L
    Feb 5, 2019 at 21:35
  • $\begingroup$ Right, but not as you descend. Getting rid of 4km/s in space is different than getting rid of 4 km/s on descent. $\endgroup$
    – ben
    Feb 5, 2019 at 21:41
  • $\begingroup$ The further from periapsis the asteroid is when you start your burn, the more delta-V it will take to accomplish, because of the Oberth Effect. $\endgroup$
    – Ryan_L
    Feb 6, 2019 at 22:44

I have been wondering if eddy currents induced in a conductive meteorite might convert some of the object's kinetic energy into heat. I found speculation about asteroid-stopping tech but this is the only article I could find dealing with the question.


abstract as image; sorry

It makes sense that a conductive object would slow as it traversed a magnetic field. The faster the object, the more it will slow. Eddy currents are affected by the shape of the object they are within, and so maybe this is less of an issue of satellites at orbital speed?

A nice thing about slowing with the earths magnetic field as opposed to aerobraking is your will not lose meteorite mass to abrasive air. A bad thing is that it might take several passes through the field to slow it down.

One could augment the magnetic braking effect by imparting an electrical charge to the asteroid. Maybe this could even be done chemically with your rocket tech. A charged object will also be affected by a magnetic field, regardless of its conductivity.

Prediction: if it is true that a (planetary) magnetic field can slow a (passing) conductive object one might expect to see deviations in the course of metallic asteroids passing the earth but not in those passing Mars which is without magnetic field.

ADDENDUM I posted my question about induction braking using planetary magnetic fields. https://astronomy.stackexchange.com/questions/29480/do-planetary-magnetic-fields-slow-the-movement-of-conductive-extraplanetary-movi

No answers yet but a comment with this very cool concept - electrodynamic tethers.

Electrodynamic tethers (EDTs) are long conducting wires, such as one deployed from a tether satellite, which can operate on electromagnetic principles as generators, by converting their kinetic energy to electrical energy, or as motors, converting electrical energy to kinetic energy.1 Electric potential is generated across a conductive tether by its motion through a planet's magnetic field.

This is perfect for steering an incoming asteroid. One could have several of these, some dedicated to braking and some to thrust akin to maneuvering jets. You use the kinetic energy of the moving body to steer it and convert that energy to heat for braking it. No moving parts. The reactionless drive!


Does a space elevator count for suitably near-future technology? No need for rockets, and having all that mass coming down to earth could drive an interesting generator for free leccy. Assuming you can find enough unobtainium to build the thing in the first place.

As for landing, does it have to be a soft landing on the ground in one big piece? If you're going to send a lot of rockets up to get the thing, could you not top each one in a cheap shuttle/X37B type vehicle to bring it down in chunks? If you could have some control over the landing maybe over a shallow sea you wouldn't need anything too sophisticated or even reuseable, just suck the debris off the seabed.

I'm not sure if the Inmarsat, Virgin and friends would appreciate you breaking up rocks in orbit given the risk of bits breaking off unexpectedly and knocking holes in satellites and tourists though.


For certain definitions of "landing" I think it might just barely be possible.

Aerobraking isn't going to do much to anything big enough to be worth playing with.

Structural integrity is going to be a big deal. If your asteroid comes apart you get Tunguska or Chelyabinsk. It better be pretty solid.

I would put the asteroid in a polar orbit as low as possible (exactly how low this is depends on your rocket technology.) The last burn lowers the periapsis (counting aerobraking effects) to a trajectory that just touches down in Antarctica as soon as it is far enough inland to not kill penguins. It's energy is expended tearing up the ice.


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