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Most weapons and artillery are split by bore diameter, e.g. naval rifles of 203mm, 406mm etc.

Railguns and coilguns probably won't be classified the same way, I think. Cause if multiple models use a 25mm slug or what have you, but they perform differently, what's a good way to separate them?

Muzzle velocity? Like a 2km/s railgun versus a 5km/s one? Or input energy? That then puts forth what's a "realistic" number to power a railgun? Output energy/impact energy have the same problem.

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  • $\begingroup$ I think velocity such as mach 10 etc $\endgroup$ – user6760 Dec 30 '18 at 2:06
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    $\begingroup$ Phased plasma rifle in the forty watt range. - The "realistic" number is in watts. You'd like to think that muzzle velocity would tell you all you need to know, but joules is really the the only important part. Most ammunition has a second number denoting its case length, but these are caseless. $\endgroup$ – Mazura Dec 30 '18 at 5:03
  • $\begingroup$ From smaller to larger: "physics toy", "the navy's on youtube?", "expensive and melted", "pipe dreams". $\endgroup$ – imallett Dec 30 '18 at 6:46
  • $\begingroup$ I assume you divide them between those allowed in carryon luggage and those that must be checked to final destination. $\endgroup$ – SRM - Reinstate Monica Jan 1 at 21:36
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As with artillery there should be some sub-types, say howitzer 88mm is quite different from a 88mm anti-air gun.

Same logic can be applied to railguns, but with the main metric being for example impact energy.

Let's say a navy 2MJ railgun with a range of 100 km, or a 50kJ man-portable one with penetration ability of 2000 mm plate steel at 5 km, etc.

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  • $\begingroup$ J = joules (the SI unit of energy) +1 $\endgroup$ – Mazura Dec 30 '18 at 5:15
  • $\begingroup$ Just a small nitpick: You won't get through two meters of steel with anything short of a serious bomb. Hypervelocity projectiles don't penetrate much into the surface of what they hit. Simply because the impact is much more like shooting a bag of golf balls into a sea of golf balls. The impact will immediately convert the energy of the projectile into heat and liquefy/evaporate the bullet and some of the armor. From that point on, the behavior is that of a strong explosion, not of a dart piercing through anything. esa.int/spaceinimages/Images/2009/02/… $\endgroup$ – cmaster Jan 2 at 8:34
  • $\begingroup$ @cmaster of course, the numbers are completely bogus. $\endgroup$ – aleck Jan 2 at 8:50
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Gauss

The gauss, abbreviated as G or Gs, is the cgs unit of measurement of magnetic flux density (or "magnetic induction") (B). It is named after German mathematician and physicist Carl Friedrich Gauss.1[2] One gauss is defined as one maxwell per square centimeter. The cgs system has been superseded by the International System of Units (SI), which uses the tesla (symbol T) as the unit of magnetic flux density.[3] One gauss equals 1×10−4 tesla (100 μT), so 1 tesla = 10,000 gauss.

I would say the best way to rate a railgun is by its Gs output.

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  • $\begingroup$ Durr. But then as mentioned, what's a good range of "realistic" numbers a future society would have on their power output? I mean, if you know. I'm about to go do some googling $\endgroup$ – armorhide406 Dec 30 '18 at 1:48
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    $\begingroup$ Useless. That doesn't tell anyone what the round will do. Gauss is only of interest to weapon designers, not to their users. $\endgroup$ – Monty Wild Dec 30 '18 at 3:39
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    $\begingroup$ Look up an ammunition on Wiki. Scroll down the side bar until you get to "Ballistic performance" : velocity should tell you how far it will go. joules (energy) tells you what it will do when it gets there. That's how all firearms should be rated. $\endgroup$ – Mazura Dec 30 '18 at 5:10
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    $\begingroup$ @MontyWild And calibur only describes the size of the bullet, not the size of the cartridge (and thus energy imparted), or really anything else about the gun. But it is still generally used as a primary identifier/rating for guns. $\endgroup$ – Xavon_Wrentaile Dec 30 '18 at 14:47
  • $\begingroup$ @monte Instead of Gauss, what about Joules? I.e. total amount of kinetic energy imparted to the object being fired? Since railguns might not be firing any standard ammo (it might be cargo transport system or, in space, any rock will do), caliber isn’t useful other than as a maximum. But joules will tell you what damage it does at impact (or how much decellerant you need to be carrying for cargo). $\endgroup$ – SRM - Reinstate Monica Jan 1 at 21:47
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Ammunition diameter x ammunition length x launch velocity, also including muzzle energy for those who don't want to work it out for themselves. They'll almost all be Armour Piercing Fin Stabilised Discarding Sabot (APFSDS) so that need not be mentioned unless different in some way, e.g.:

5x50mm 5km/s 98kJ Steel

This could be a man-portable crew-served tripod weapon or vehicle mounted railgun firing steel flechettes

Or, a more terrifying ship-launched:

50x1000mm 7km/s 919MJ DU Guided

Which would be a depleted uranium flechette with a guidance package used for bunker busting.

Or a tank-launched:

20x400mm 4km/s 19.2MJ DU

That pretty much gives all the information that anyone with any knowledge of ballistics would need to work out the terminal effects of the round and its flight performance.

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Joules.

... but for railguns, it's the 'cartage' that will have the rating, and the rifle will have to be approved to fire it: "Chambered for the popular XM107 round!"


.308 verses .50 BMG

enter image description hereenter image description here

But those are just numbers that would make us wonder if it will penetrate 3/4 inch thick steel plate at 200 yards (which is no and yes, respectively). However that's the only single number to look at for "ballistic performance".

I think that if or when they come to market, railguns will be (hopefully) named akin to their caliber, but they will be rated in the largest weight 'cartage' that they can chamber and reliably fire. In all actuality, it's going to be called by whatever name given by whatever manufacturer produces the most prolific round (and eventually appear as a truncated, standardized version as deemed by the government). Often, new weapons are specifically made to use a premier cartage; not the other way around - they're at the very least, made alongside (I'm so tired of video games that a new rifle drastically changes everything, all the while firing the same cartage...).

They will not be rated in muzzle velocity because as you can see, the differences between those two cartridges is negligible, but their impact is not, due to a .50 BMG being about four times the weight of a .308, and traveling at basically the same speed.

The problem with portable railguns is their imaginary power supplies. Who knows, they might be called iRifles. Whatever they're called, the bottom line I'm looking for on a projectile is energy on target.

Perhaps the nomenclature will be as thus: "Certified to fire [XXX] grain, [.XX] caliber projectiles, at the UN specified minimum speed of 3k ft/s." ... because you're relying on the rifle to accelerate the projectile, the manufacturer of the rifle will have to be acclaimed by the projectile manufacturer (whom would get to name the cartage). Call the rifle whatever you want; it has to be rated to fire (in specific calibers, obviously) a given weighted projectile (at the more or less acceptable speed of 3k ft/s).


TL;DR: some combination of weight and caliber. One tells me if it fits in my gun, the other tells me how much of a mess it's going to make.

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    $\begingroup$ ... and how much it's going to hurt my shoulder - equal and opposite reactions beyond 3k joules are no joke, without an intricate recoil system. $\endgroup$ – Mazura Dec 30 '18 at 9:19
  • $\begingroup$ 3,000 ft/s - otherwise WTF, then I just want my M14! $\endgroup$ – Mazura Dec 30 '18 at 9:27
  • $\begingroup$ The rifle may or may not be rated in joules but the projectile, as always, will be rated in grains. $\endgroup$ – Mazura Dec 30 '18 at 9:49
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Current researchers classify railguns by their muzzle energy, such as the US Navy's 32MJ railgun, and researchers were looking to double the energy to 64MJ.

This really is independent of the size and mass of the projectile, you could have a 64MJ railgun firing a very small pellet at hypersonic velocity, or large cannonball shaped projectiles at a much lower velocity. However, we accept that current chemical tube artillery can have very different trajectories and terminal effects even if the same calibre; for example a 105mm howitzer has a much different profile than a 105mm L7 tank cannon (or a 106mm recoiless rifle, which was actually 105mm in calibre, but marked "106" to prevent confusion in the logistics train)

enter image description here

105mm Howitzer

enter image description here

105mm L7 on a German tank

enter image description here

106mm recoiless rifle

So railguns and electromagnetic cannon in general could be characterized by their muzzle energy, without too much distinction between the actual role of the weapon. This could be a secondary descriptor i.e. 64MJ naval surface bombardment railgun or 10MJ naval antimissile railgun.

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[ammunition diameter] by [exit velocity]

Essentially, you notate the diameter of the weapon's accommodation, and then notate how fast it can get a slug of that size going. That latter would probably be a range of velocities, given that different lengths of slug will take different energy inputs to accelerate.

Also consider if you want to be able to shoot to wound instead of shooting to kill. Chemical propulsion doesn't allow for that, but a railpistol might.

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    $\begingroup$ Without length, you can't know the potential penetration. $\endgroup$ – Monty Wild Dec 30 '18 at 3:37
  • $\begingroup$ @MontyWild - Length doesn't really matter until it's way out of proportion. Projectiles are classified by weight in grains. $\endgroup$ – Mazura Dec 30 '18 at 5:17
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    $\begingroup$ @Mazura, when you are talking about railgun rounds, projectile density and length are very important - they are two of the factors that come into play in Newton's impact depth approximation en.wikipedia.org/wiki/Impact_depth $\endgroup$ – Monty Wild Dec 30 '18 at 6:45
  • $\begingroup$ @MontyWild - "This approach only holds for a blunt impactor (no aerodynamical shape)" - almost all projectiles are parabolic as it's the most aerodynamic shape. Given a material, a weight, a caliber, and assumed to be parabolic: a length can be determined/estimated - not that its weight changes awfully much with a different tip. And as E=MC^2, its weight times its velocity will tell you the amount of energy imparted upon impact. E.g., a .30cal is ~3k joules. A .50 BMG is ~13kJ. (because it weighs four times as much; it's only going slightly faster). They're both pretty much the ideal shape. $\endgroup$ – Mazura Dec 30 '18 at 7:18
  • $\begingroup$ @Mazura, that's why Newton's impact depth approximation is an approximation. However, when we're talking about long-rod penetrators moving at speeds measured in kilometres per second, its a useful approximation. However, even a flat-nosed DU rod will self-sharpen as Uranium tends to fracture in a way that leads to it having a rough point in high velocity impact scenarios. That's one reason why DU is used and not Osmium. $\endgroup$ – Monty Wild Dec 30 '18 at 10:38

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