Let's talk Physics!
Ok, what is Plasma? Plasma is a very specific state of matter, that is also known as the fourth state of matter. under normal conditions it doesn't exist, and on earth usually is achieved by heating and compressing gases and applying a current. When the current flows through the plasma, it lifts electrons to higher states, which emits light as they bounce back. The wavelength is dependant on the energy gap between the energized and normal state, and thus dependant on the matter that is in plasma state.
Colorful Light!
aka "Luninescense of gases from electron avalance in a discharge tube"
Both Neon and Argon are relatively known examples, because these noble gases are abundantly used in light tubes. Neon is the telltale orange-red, Argon a pale purple, Xenon a blue and Helium as well as Krypton tones of yellow. Hydrogen is a red-purple, deuterium is "sith red", nitrogen a vibrant purple, mercury a bright white-blue. So we can have different glowing plasmas easily. But what about them using the exact same device but for the contents of the gas-tank?!
I found a general number, that one foot of neon light would draw 3.5 to 4 Watts, but couldn't find such numbers for the other gases. But because the gap to the next eectron level slims down the larger the atom is, I expect slightly smaller numbers for all but Helium to achieve luminescense.
And just because everybody loves pictures:
BUT...
But the plasma in neon lights is relatively cold and does not react well to unconfined space. So, the plasma might (also?) get its color from a different source but the gas composition.
Heat
There is a different thing people always forget when dealing with plasma, and that is, that its properties are in long stretches a little gaslike, and thus the formulas for gases are used to make very rough estimates. For example $pV=nRT$, the gas law. There is pressure, Volume, number of mols of atoms involved, Gas constant R and finally Temperature1. Combine this with the light emitted by a black body from the Stefan-Boltzman law ($j^*=\sigma T^4$, where $\sigma=5.56\times 10^-8 \frac{\text W}{\text m^2 \text K^4}$), we get this monster:
(1) $\frac{pV}{nR}=T$
(2) $j^*= \sigma T^4 = \sigma (\frac{pV}{nR})^4$
So the result is, that our emitted light spectrum is dependant on the temperature2, which in turn can be modeled via the gas law (to some degree) as being just dependant on pressure and volume. To reach a high temperature, let's say 6000K to get a golden sun orange glowing fireball, we can grab our other properties to look at what we need. Let's say our gun has a chamber of 1 cm² cut area and 5 cm length, so 5cm³ volume ($5 \times 10^{-6}\text m^3$).
$\frac {T R} V = \frac p n$
Our Pressures are pretty high if we want to conserve ammo: 1 mol of gas under 1 atmosphere is 22.4 liters - or if we have a box with 1 m² area, it stacks about 22.4 mm high, about a finger wide or almost an inch. A standard gas container uses about 200 bar and stores 200 liters of standard condition gas in 1 liter. Assuming a nice half liter gas tank and 200 bar storage pressure, we can carry around the number of atoms usually in 100 liters of gas at standard pressure. That's about 4.46 mol in the bottle. NOW comes the tricky part: for each shot, we will need gas, so we need to portion it. Let's assume for simplicity that we have 111 shots of 0.04 mol3. Then our pressure would need to be an astonishing $399.072\ \text{MPa}$ 4.
And, because pictures: pick your temperature and luminosity from the Hertzsprung Russel Diagram for possible values.
Conclusion
Yes, it is certainly possible to color your laser-heated plasma bolts to your liking using two screws: the gas used as plasma-precursor and the temperature of the plasma itself. To change the plasma temperature, one could directly assault the issiue of the temperature by using more power on the lasers, or one could alter the gas flow per shot, indirectly altering temperature via the changed pressure(1). And the temperature results in the color of light emission, because of the properties of a black body.
Tuning your plasma color
So, to get other plasma colors using the same base weapon, one could do this:
- Use a different gas composition to turn into plasma.
- Bore open the containment cylinder to lessen pressure and lower temperature for a more red look - and maybe safety reasons.
- Set the valve for the shots to be less open for more shots - and a more red look.
- Open the valve more for less shots but a blue style and the risk of blowing the gun in your hand.
- Exchange the heating lasers for more powerful ones for more blue.
1 - There is a different notation using $pV=Nk_BT$ with N being the absolute number and kB the Boltzman constant, but both are mathematically aequivalent.
2 - This is not taking into account anything BUT light to transfer energy away. Also, there would be more to this formula - I use the simplified version over all the spectrum here, not the wavelength specific one, that is material dependant.
3 - Let's ignore that the work to remove a set portion of gas from a container is pressure differential dependent. It is easier to let a set amount out of a high-pressure container than to get the same amount from a lower pressure container.
4 - With pressures like that I would not want to hold that gun in my hand. CERN struggles to build up those pressures in their accelerators. And they use more temperature even.