The strain, $h$, of a gravitational wave is
$$h\sim\frac{1}{R}\frac{GM}{c^2}\left(\frac{v}{c}\right)^2$$
to a relatively decent degree of accuracy. Here, $R$ is the distance to the source, $M$ is the combined mass of the black holes, and $v$ is the orbital speed of the binary. If we gratuitously assume that $v\sim0.1c$ and $M\sim50M_{\odot}$, then at one astronomical unit (AU) away, the same distance Earth is from the Sun, we find that $h\sim5\times10^{-4}$. In order to detect the waves, the species' "eyes" would need to detect a change in a meter-long object of half a millimeter - and that's with them living dangerously close to the black hole binary! Maybe extremely small lifeforms - bacteria, perhaps - would notice such a change, but macroscopic, human-sized lifeforms would not.
Now, this $h$ is greater than the strain measured by LIGO, which was on the order of $10^{-21}$, so in general, it should be easier to measure. However, it seems highly improbable that the species would involve mini laser interferometers as eyes.
It's true that the orbital speed of the black holes would increase as they begin to coalesce. Abbott et al. (2016) - the discovery paper announcing LIGO's observations that was published earlier this year - showed a maximum speed of about $0.6c$ (see Fig. 2):
Given that $h\propto v^2$, this causes an increase in $h$ of about 36 (also, $M\sim70M_{\odot}$ for the LIGO binary), giving us a length change of 1 cm for 1-meter object, which is certainly detectable, but and it lasts for only a very short amount of time before the source stops producing gravitational waves (post-coalescence).
If we put these aliens near an area full of black hole binaries - never mind the absurdity involved in the formation of such a cluster, or the likely instabilities that could break it apart - we have the problem that different binaries could interfere with one another. Gravitational waves are . . . well, waves, and so are subject to constructive and destructive interference.
A simple metric for the expansion and contraction of spacetime by a point source of gravitational waves coming along the $z$-axis is
$$ds^2=dt^2-\left[(1+2H(t,z))dx^2+(1-2H(t,z))dy^2+dz^2\right]$$
where
$$H(t,z)=h\cos\left[2\pi f(t-z/v)\right]$$
for frequency $f$ and speed $v$ (which should be $c$). This should make the actual wave nature of gravitational waves clearer. If we have two sources of gravitational waves aligned along the same axis, then they can either increase the strength of the signal or significant decrease it, depending on their respective strains and the values of their $t-z/v$. More complex interactions occur when different waves are at other odd angles to one another.
I realize that I should apologize to the curious reader who may want to know more, because I looked at my notes and used non-standard notation. If you look at most papers on the subject, you'll see the quantity I referred to as $h$ denoted by $h_0$, and the quantity I referred to as $H(t,z)$ denoted by $h(t)$, where we set $z=0$. Therefore, you'd really see the equations
$$h_0\sim\frac{1}{R}\frac{GM}{c^2}\left(\frac{v}{c}\right)^2,\quad h(t)=h_0\cos\left(2\pi ft\right)$$
for the case of a binary system moving together at a very slight rate. The first one might be written in terms of the orbital frequency of the system, but I prefer using this form for an easy approximation.