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The correct formula to use here, given constant acceleration, to use here is... Vf² - Vi² = 2 * a * d.

So... a = (Vf² - Vi²) / (2 * d)

Vf = 310km/h = 86.11 m/s
Vi = 0 m/s
d = 250m

you get an acceleration of 14.83m/s² or about 1.50 g. This is well within human limits.

The correct formula to use here, given constant acceleration, is $v_f^2 - v_i^2 = 2ad$.

So $$a = \frac{v_f^2 - v_i^2}{2d}$$ with $$\begin{align} v_f &= 310\ \mathrm{km/h} = 86.11\ \mathrm{m/s} \\ v_i &= 0\ \mathrm{m/s} \\ d &= 250\ \mathrm{m} \end{align}$$ you get an acceleration of $14.83\ \mathrm{m/s^2}$ or about $1.50g$. This is well within human limits.

The correct formula to use here, given constant acceleration, to use here is... Vf² - Vi² = 2 * a * d.

So... a = (Vf² - Vi²) / (2 * d)

With

Vf = 310km/h = 97.22 m/s
Vi = 0 m/s
d = 250m

you get an acceleration of 14.83m/s² or about 1.50 g. This is well within human limits.

The correct formula to use here, given constant acceleration, to use here is... Vf² - Vi² = 2 * a * d.

So... a = (Vf² - Vi²) / (2 * d)

With

Vf = 310km/h = 86.11 m/s
Vi = 0 m/s
d = 250m

you get an acceleration of 14.83m/s² or about 1.50 g. This is well within human limits.

The correct formula to use here, given constant acceleration, to use here is... Vf² - Vi² = 2 * a * d.

So... a = (Vf² - Vi²) / (2 * d)

With 350k m/h = 97.22 m/s as your Vf, and 0 as your Vi, and 250m as your distance, you get an acceleration of 18.9 m/s² or about 1.92 g. This is well within human limits.

The correct formula to use here, given constant acceleration, to use here is... Vf² - Vi² = 2 * a * d.

So... a = (Vf² - Vi²) / (2 * d)

With

Vf = 310km/h = 97.22 m/s
Vi = 0 m/s
d = 250m

you get an acceleration of 14.83m/s² or about 1.50 g. This is well within human limits.