Timeline for Could a binary planet system have two non-tidally-locked Earth-like planets?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 18, 2016 at 2:49 | comment | added | Xandar The Zenon | There will be eclipses, though, which make for unusually long nights. | |
| Mar 17, 2016 at 21:36 | vote | accept | greatconcavity | ||
| Mar 17, 2016 at 20:55 | comment | added | Jim2B | You are overthinking it. Only the planet's rotation affects the duration of the day-night cycle. | |
| Mar 17, 2016 at 20:25 | comment | added | greatconcavity | Thanks! Are you sure about the day/night cycle? Since each planet is rotating in relation to the sun both axially and in its binary orbit, wouldn't day length fluctuate (even if very slightly) in some sort of increasing-and-decreasing cycle? Or am I overthinking this? | |
| Mar 17, 2016 at 19:50 | comment | added | Tim B | @MikeScott Thanks, just finished looking that up myself. I know it was greater than squared but wasn't sure the amount off hand. :) | |
| Mar 17, 2016 at 19:50 | history | edited | Tim B | CC BY-SA 3.0 |
added 34 characters in body
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| Mar 17, 2016 at 19:45 | comment | added | Mike Scott | Tidal forces follow an inverse cube law, not inverse square. If they didn't then Earth's tides would be dominated by the sun rather than the moon. So a planet with 100x the mass of the moon that was ten times as far away as the moon would actually have 1/10th of the tidal effect that the moon has, 100/1000. | |
| Mar 17, 2016 at 19:38 | history | answered | Tim B | CC BY-SA 3.0 |