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You're probably not going to be able to escape by going down.

This paper gives equations to calculate the psi from a variable TNT equivalent bomb at a variable depth under the water (in feet, sorry) from the explosion on the surface.

$P = 0.7 * 2.16 \times 10^4 ({{W^{1/3}}\over{R}})^{1.13}$

Where $P$ is the overpressure in psi, the 0.7 coefficient is the attenuation due to being above the surface, $W$ is the charge weight in pounds, and $R$ is the range in feet.

The questions are derived empirically from this data:

In your case, for a 1MT bomb, things don't look good. Your ship is probably able to go to at least 1,000 ft underwater (to collect the gold). In sea water that's about 460 psi. The overpressure from a 1MT surface detonation at 1,000 feet underwater is over 1,100 psi. So, unless your submersible has a pressure safety factor of over three times the operating depth, you're not likely to survive.

I don't know your planned depth, but I will estimate you have a safety factor of 20%. Given that information I can see that if you designed for 3,240 feet, and dove to that depth, the overpressure would just be inside your safety margins.

Note that the blue line only appears to be going back up because the additional overpressure has stopped diminishing faster than the growth of pressure at increasing depth.

You're probably not going to be able to escape by going down.

But this depends on what depth your ship was designed to withstand.

This paper gives equations to calculate the psi from a variable TNT equivalent bomb at a variable depth under the water (in feet, sorry) from the explosion on the surface.

$P = 0.7 * 2.16 \times 10^4 ({{W^{1/3}}\over{R}})^{1.13}$

Where $P$ is the overpressure in psi, the 0.7 coefficient is the attenuation due to being above the surface, $W$ is the charge weight in pounds, and $R$ is the range in feet.

The questions are derived empirically from this data:

In your case, for a 1MT bomb, things don't look good. Your ship is probably able to go to at least 1,000 ft underwater (to collect the gold). In sea water that's about 460 psi. The overpressure from a 1MT surface detonation at 1,000 feet underwater is over 1,100 psi. So, unless your submersible has a pressure safety factor of over three times the operating depth, you're not likely to survive.

I don't know your planned depth, but I will estimate you have a safety factor of 20%. Given that information I can see that if you designed for 3,240 feet, and dove to that depth, the overpressure would just be inside your safety margins.

Note that the blue line only appears to be going back up because the additional overpressure has stopped diminishing faster than the growth of pressure at increasing depth.

You're probably not going to be able to escape by going down.

This paper gives equations to calculate the psi from a variable TNT equivalent bomb at a variable depth under the water (in feet, sorry) from the explosion on the surface.

$P = 0.7 * 2.16 \times 10^4 ({{W^{1/3}}\over{R}})^{1.13}$

Where $P$ is the overpressure in psi, the 0.7 coefficient is the attenuation due to being above the surface, $W$ is the charge weight in pounds, and $R$ is the range in feet.

The questions are derived empirically from this data:

In your case, for a 1MT bomb, things don't look good. Your ship is probably able to go to at least 1,000 ft underwater (to collect the gold). In sea water that's about 460 psi. The overpressure from a 1MT surface detonation at 1,000 feet underwater is over 1,100 psi. So, unless your submersible has a pressure safety factor of over three times the operating depth, you're not likely to survive.

I don't know your planned depth, but I will estimate you have a safety factor of 20%. Given that information I can see that if you designed for 3,240 feet, and dove to that depth, the overpressure would just be inside your safety margins.

You're probably not going to be able to escape by going down.

This paper gives equations to calculate the psi from a variable TNT equivalent bomb at a variable depth under the water (in feet, sorry) from the explosion on the surface.

$P = 0.7 * 2.16 \times 10^4 ({{W^{1/3}}\over{R}})^{1.13}$

Where $P$ is the overpressure in psi, the 0.7 coefficient is the attenuation due to being above the surface, $W$ is the charge weight in pounds, and $R$ is the range in feet.

The questions are derived empirically from this data:

In your case, for a 1MT bomb, things don't look good. Your ship is probably able to go to at least 1,000 ft underwater (to collect the gold). In sea water that's about 460 psi. The overpressure from a 1MT surface detonation at 1,000 feet underwater is over 1,100 psi. So, unless your submersible has a pressure safety factor of over three times the operating depth, you're not likely to survive.

I don't know your planned depth, but I will estimate you have a safety factor of 20%. Given that information I can see that if you designed for 3,240 feet, and dove to that depth, the overpressure would just be inside your safety margins.

Note that the blue line only appears to be going back up because the additional overpressure has stopped diminishing faster than the growth of pressure at increasing depth.

You're probably not going to be able to escape by going down.

This paper gives equations to calculate the psi from a variable TNT equivalent bomb at a variable depth under the water (in feet, sorry) from the explosion on the surface.

$P = 0.7 * 2.16 \times 10^4 ({{W^{1/3}}\over{R}})^{1.13}$

Where $P$ is the overpressure in psi, the 0.7 coefficient is the attenuation due to being above the surface, $W$ is the charge weight in pounds, and $R$ is the range in feet.

The questions are derived empirically from this data:

In your case, for a 1MT bomb, things don't look good. Your ship is probably able to go to at least 1,000 ft underwater (to collect the gold). In sea water that's about 460 psi. The overpressure from a 1MT surface detonation at 1,000 feet underwater is over 1,100 psi. So, unless your submersible has a pressure safety factor of over three times the operating depth, you're not likely to survive.

You're probably not going to be able to escape by going down.

This paper gives equations to calculate the psi from a variable TNT equivalent bomb at a variable depth under the water (in feet, sorry) from the explosion on the surface.

$P = 0.7 * 2.16 \times 10^4 ({{W^{1/3}}\over{R}})^{1.13}$

Where $P$ is the overpressure in psi, the 0.7 coefficient is the attenuation due to being above the surface, $W$ is the charge weight in pounds, and $R$ is the range in feet.

The questions are derived empirically from this data:

In your case, for a 1MT bomb, things don't look good. Your ship is probably able to go to at least 1,000 ft underwater (to collect the gold). In sea water that's about 460 psi. The overpressure from a 1MT surface detonation at 1,000 feet underwater is over 1,100 psi. So, unless your submersible has a pressure safety factor of over three times the operating depth, you're not likely to survive.

I don't know your planned depth, but I will estimate you have a safety factor of 20%. Given that information I can see that if you designed for 3,240 feet, and dove to that depth, the overpressure would just be inside your safety margins.