Timeline for Vertical City - How High?
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Nov 19, 2015 at 7:12 | comment | added | Tim B | Is it 2 times or 8 times? If it is 2 times we have linear. 4 times square. 8 times cube. Your equations look reasonable but 2nd paragraph looks wrong. | |
Nov 19, 2015 at 4:58 | history | edited | Jim2B | CC BY-SA 3.0 |
added 258 characters in body
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Nov 19, 2015 at 4:57 | comment | added | Jim2B | But you notice at the very beginning that I specify an assumption of a square building shape - thus we do suffer the square / cube problem. Either way it doesn't matter. The amount of area required to support a height goes up linearly with that height (because it is still holding up a volume of material). So the equation remains the same even if the size of the building does not. | |
Nov 18, 2015 at 23:13 | comment | added | Tim B | Animals expand in 3 dimensions which is where the square cube stuff comes in, this is a different case though. | |
Nov 18, 2015 at 23:12 | comment | added | Tim B | Nope. It scales as a cube if expanding in 3 dimensions. We only expanding in one though so it is linear. A tower twice as high...does it weigh twice as much as or eight times? | |
Nov 18, 2015 at 21:59 | comment | added | Jim2B | Yes, that's the square / cube problem. Strength scales as the square of linear distance (area) while weight scales as the cube of the linear distance (volume). So the limiting case is the "first floor" is solid structural material - which is the case I used above. | |
Nov 18, 2015 at 21:14 | comment | added | Tim B | You're growing vertically upwards so actually weight scales linearly and strength doesn't scale at all.... | |
Nov 11, 2015 at 0:11 | history | answered | Jim2B | CC BY-SA 3.0 |