Timeline for How can the neutron star factory make heavy elements?
Current License: CC BY-SA 4.0
12 events
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Nov 18, 2022 at 16:13 | comment | added | DKNguyen | @tom There is one workaround: the shell radius is so unimaginably large around the star that the power per area is tolerable. Although.... not sure if that would just collapse into a black hole or another neutron star. The OP's proposed shell size might already do that. | |
Nov 16, 2022 at 22:26 | answer | added | Juraj | timeline score: 1 | |
Nov 16, 2022 at 1:08 | history | edited | Arcturus | CC BY-SA 4.0 |
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Nov 15, 2022 at 20:38 | comment | added | ShadoCat | One theory is that neutron stars do this already as protons hit and get stuck in the outer "skin" of the neutron star. | |
Nov 15, 2022 at 12:51 | comment | added | Arcturus | @Daron Beryllium is for reflecting the neutrons back onto the hydrogen. Iron is used for blocking ionizing radiation. | |
Nov 15, 2022 at 12:14 | comment | added | Daron | But why Berrylium? | |
Nov 15, 2022 at 12:12 | history | edited | Daron | CC BY-SA 4.0 |
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Nov 15, 2022 at 11:13 | answer | added | Starfish Prime | timeline score: 3 | |
Nov 14, 2022 at 18:18 | answer | added | Jobah_HigherMind | timeline score: 1 | |
Nov 14, 2022 at 17:54 | answer | added | L.Dutch♦ | timeline score: 1 | |
Nov 14, 2022 at 17:52 | comment | added | Tom | That beryllium shell will immediately melt. It completely encloses the stark, which means it receives 100% of the energy emitted by the star. I would expect it to melt or otherwise disintegrate in just a few seconds. There can be no workaround: if you completely enclose the star, your enclosure will absorb all the energy emitted by it. | |
Nov 14, 2022 at 17:13 | history | asked | Arcturus | CC BY-SA 4.0 |