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Apr 12, 2022 at 14:07 comment added Daron You are right. The gradient is the important one. But I am getting about 10^30 / 10^11 = 10^19 for the sun's gradient and only 10 ^23 / 10^8 = 10^15 for the moon. That suggests the Solar tides are larger than the Lunar tides.
Apr 12, 2022 at 13:15 comment added Jon Custer See oceanservice.noaa.gov/education/tutorial_tides/… for example. Note that it is the gradient, not absolute value, of the gravitational interaction that leads to tides.
Apr 12, 2022 at 13:10 comment added Daron I was trying to check that by comparing the gravitational pull of the sun vs the moon. What a silly question. Of course the sun exerts more gravity. That's why we orbit the sun and not the moon!
Apr 12, 2022 at 13:00 comment added Jon Custer The tidal bulge from the sun is about half that from the moon. So, tidal heights would be constant and about 1/3 of peak (sun+moon) tides. I don't consider 1/3 to be 'itty bitty'.
Apr 12, 2022 at 12:57 comment added Daron @JonCuster Itty bitty Solar tides.
Apr 12, 2022 at 1:18 comment added Jon Custer There would still be (smaller) tides.
Apr 11, 2022 at 23:16 history answered Daron CC BY-SA 4.0