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Oct 22, 2021 at 19:53 comment added bukwyrm @AdrianColomitchi : Your reasoning is true, as far as "input=output -> steady state" goes, but the whole earth surface is radiating, while only half is receiving sunlight at any given point (and that is any sunlight, counting midday on the equator and dusk in Antarctica). I took the guesstimate from this graph (earthobservatory.nasa.gov/ContentFeature/EnergyBalance/images/…) in the article linked in my answer - it might be slightly higher or lower, but +-100W
Oct 20, 2021 at 5:51 comment added Adrian Colomitchi Since Earth maintains an almost constant temperature, it follow that the total loss by radiation at night must be pretty close with the radiation received on the sunny side (- energy stored in biomass - photosynthesis efficiency in the 6% range). I think you'd be safe to assume a radiation loss way higher than 200W/sqm. That NASA link at the end of the Q states "The energy that Earth receives from sunlight is balanced by an equal amount of energy radiating into space."
Oct 20, 2021 at 5:12 history edited bukwyrm CC BY-SA 4.0
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Oct 19, 2021 at 21:54 history answered bukwyrm CC BY-SA 4.0