Timeline for What forces should I consider for my hotel room on the Space Elevator?
Current License: CC BY-SA 3.0
5 events
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Jun 3, 2015 at 0:54 | comment | added | evankh | My mistake - I didn't account for rotation. This answer should be correct for a very tall tower supporting its own weight, but not a counterweight supported by centrifugal force. | |
Jun 2, 2015 at 20:27 | comment | added | Samuel | Not quite right, you left out the math that makes space elevators work. If the counterweight experiences net acceleration towards the planet (which would be the case if "they should be able to stand on the earthward wall of the station") then the entire system will fall out of the sky. The apparent acceleration would be in the opposite direction. | |
Jun 2, 2015 at 10:31 | comment | added | Murphy | not perfectly so: items would slowly drift to one wall. A brick dropped down a 100 meter shaft would take 44 seconds to reach the bottom but by then it would be traveling at about 4.4m/s and would hit you like a brick dropped from about 1.25 meters above your head at ground level. | |
Jun 2, 2015 at 8:23 | comment | added | Mikey | #4 - Is it as easy as this? I imagined there would be some kind of pull, but I suppose that is on the counterweight, not on my guests chilling out at the cocktail bar on the counterweight. They're indeed experiencing the same sensation as on space stations? | |
Jun 2, 2015 at 7:08 | history | answered | evankh | CC BY-SA 3.0 |