Timeline for Building a phone charger 500 years ago
Current License: CC BY-SA 4.0
21 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Oct 23, 2019 at 7:25 | comment | added | Walter Mitty | Another factor influencing voltage is the internal impedance of the battery arrangement. The more current flowing, the lower the effective voltage will be. You might be able to design the battery arrangement so that it operates like a poor man's regulator, effectively reducing the voltage from 1.1V to 1.0V per cell, which is what you want. | |
Oct 22, 2019 at 6:52 | comment | added | Bruce Abbott | Zinc wasn't readily available in Europe until the 17th century. You would have to go to India, or mine and smelt it yourself. Alloys such as brass would not work very well. You don't need a voltmeter if you know what voltage your cells produce (depends on the metals - zinc/copper is 0.95V per cell, Lead/copper is 0.435V). | |
S Oct 22, 2019 at 4:39 | history | edited | ltmauve | CC BY-SA 4.0 |
Minor spelling and grammar fixes.
|
S Oct 22, 2019 at 4:39 | history | suggested | B-K | CC BY-SA 4.0 |
Minor spelling and grammar fixes.
|
Oct 22, 2019 at 1:35 | review | Suggested edits | |||
S Oct 22, 2019 at 4:39 | |||||
Oct 21, 2019 at 21:57 | comment | added | Dragongeek | Assuming your phone is easy to open and access, you could build an analog voltmeter with a coil of wire and a ferromagnetic dial indicator. Then, calibrate the voltmeter by measuring the voltage on the battery cells in your phone (around 3 volts) and use that to extrapolate to 5 volts. | |
Oct 21, 2019 at 21:52 | comment | added | Harabeck | You should probably update your answer with useful information instead of telling readers to check the comments. The answer itself should have the... well answer. Comments are for suggesting improvements. | |
Oct 21, 2019 at 20:32 | history | migrated | from electronics.stackexchange.com (revisions) | ||
Oct 21, 2019 at 18:12 | comment | added | Michel Keijzers | @StainlessSteelRat :-) | |
Oct 21, 2019 at 18:01 | comment | added | StainlessSteelRat | Bring me a potatoe (and some zinc and copper nails). Down with the witch! | |
Oct 21, 2019 at 13:56 | comment | added | Hearth | @JRE Technically aluminum was known before it was able to be produced from ore. Native aluminum was exceptionally rare and expensive though, and I don't think it was known in 1500 either, anyway. | |
Oct 21, 2019 at 10:46 | comment | added | Michel Keijzers | @JRE True thanks (according to my answer, but I will clearify it), The element Zinc was discovered in 1746 but the alloy was known before that. | |
Oct 21, 2019 at 10:44 | comment | added | JRE | No aluminum in 1500. Aluminum metal was first produced in 1824. | |
Oct 21, 2019 at 10:37 | comment | added | Michel Keijzers | @JRE I already changed it into Volt meter, but you would need indeed a good reference. I will add that too. | |
Oct 21, 2019 at 10:32 | comment | added | JRE | You'd want a voltmeter rather than an ammeter. We're back to the same old "do I match the voltage or current of the powersupply to the device?" But, you haven't got much chance if calibrating your voltmeter so it will be of limited use. | |
Oct 21, 2019 at 10:30 | comment | added | Michel Keijzers | @C1sc0 Yes, thanks, I replaced it. | |
Oct 21, 2019 at 10:15 | comment | added | analogsystemsrf | use a lode-stone (magnetic material) and the silver wiring needed in fine-detail jewelry; simply have a pendulum move the lode-stone in and out of the wire coil | |
Oct 21, 2019 at 10:14 | comment | added | Dirk Bruere | Zinc and Copper would provide 1.1V per cell | |
Oct 21, 2019 at 10:10 | comment | added | Bytes | Hmm, I guess the factors controlling voltage output would be your electrolyte (probably controllable by making up your own salt solution), metal purity (a bit more difficult at that time) and general construction technique (probably fairly well controllable). | |
Oct 21, 2019 at 10:01 | comment | added | IamK | You mean voltage meter instead of ampere meter?! | |
Oct 21, 2019 at 9:48 | history | answered | Michel Keijzers | CC BY-SA 4.0 |