Timeline for Would a horse be sufficient buffer to prevent injury when falling from a great height?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Oct 3, 2019 at 5:53 | comment | added | vinchenso | @Scott actually I think spherical assumptions just require you to take the integral of your displacement equation with radius initial conditions. Harder is when you model the energy transfer as a second order system of springs, viscous dampeners and inertial masses! But I guess that would just a case of flogging a dead horse! XD | |
| Oct 2, 2019 at 15:12 | comment | added | Him | @vinchenso, spheres would make the problem much harder. This only works when both the person and the horse are point masses. :) | |
| Oct 2, 2019 at 13:50 | comment | added | vinchenso | I'm thoroughly disappointed by the severe lack of spherical horse assumptions in this proof. | |
| Sep 25, 2019 at 17:36 | comment | added | Him | @Vaelus could be. Linearly increasing force means linearly increasing acceleration. Since we need to get to 0 velocity, and velocity is the integral of acceleration, it is instructive to note that a linearly increasing acceleration from 0 with an equal area under the curve to a constant acceleration has double the maximum acceleration (by just some geometric maneuvering). So, if you want a spring instead of an ideal cushion, the maximum attained acceleration is double all of the accelerations in my analysis. | |
| Sep 25, 2019 at 16:58 | comment | added | Vaelus | Perhaps it would be better to model the horse as an ideal spring, i.e., a cushion with linearly increasing force. | |
| Sep 25, 2019 at 2:29 | history | answered | Him | CC BY-SA 4.0 |