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ArtificialSoul
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The momentum theorem states that $m\times\delta v = F\times \delta t$, or $ F = m \times \delta v /\delta t$

Putting in that formula your numbers, we get $ F = 1300 \times 27/0.001 = 35.1 \times 10^6 N$$ F = 1300kg \times \frac{27\frac{m}{s}}{0.001s} = 35.1 \times 10^6 N$

That's a huge force, and that's what normally happens when a car hits a hard and non movable obstacle. Maybe quicker.

What kills you is not the velocity, but the sudden deceleration

All that kinetic energy will be converted to plastic deformation and then to heat.

The momentum theorem states that $m\times\delta v = F\times \delta t$, or $ F = m \times \delta v /\delta t$

Putting in that formula your numbers, we get $ F = 1300 \times 27/0.001 = 35.1 \times 10^6 N$

That's a huge force, and that's what normally happens when a car hits a hard and non movable obstacle. Maybe quicker.

What kills you is not the velocity, but the sudden deceleration

All that kinetic energy will be converted to plastic deformation and then to heat.

The momentum theorem states that $m\times\delta v = F\times \delta t$, or $ F = m \times \delta v /\delta t$

Putting in that formula your numbers, we get $ F = 1300kg \times \frac{27\frac{m}{s}}{0.001s} = 35.1 \times 10^6 N$

That's a huge force, and that's what normally happens when a car hits a hard and non movable obstacle. Maybe quicker.

What kills you is not the velocity, but the sudden deceleration

All that kinetic energy will be converted to plastic deformation and then to heat.

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L.Dutch
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The momentum theorem states that $m\times\delta v = F\times \delta t$, or $ F = m \times \delta v /\delta t$

Putting in that formula your numbers, we get $ F = 1300 \times 27/0.001 = 35.1 \times 10^6 N$

That's a huge force, and that's what normally happens when a car hits a hard and non movable obstacle. Maybe quicker.

What kills you is not the velocity, but the sudden deceleration

All that kinetic energy will be converted to plastic deformation and then to heat.